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anastassius [24]
3 years ago
7

What is Quadratic inequality

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0
Quadratic in equality is quadratic function that is compared to another function like: x^2+4x-1<2x-3. the answer for x must comply to both sides.
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Which number belongs to the solution set of the equation below? 8x=120
vlabodo [156]
8x = 120
x = 120/8
x = 15
4 0
3 years ago
What is the fifth term of the geometric sequence? 5, 15 , 45, ...
Virty [35]

The geometry sequence has the equation a(n)=5(3^{n-1}).

The 5 represents the first number of the sequence and the 3 represents the common ratio.

a(5) = 5(3^{5-1})=5(3^{4})=5(81)=405

answer: 405

6 0
3 years ago
Joe has saved $50. He wants to
denis23 [38]

Answer: Yes, because he will be spending a total of $39 dollars.

Step-by-step explanation

$13 + $13 + $13 = $39

5 0
3 years ago
Read 2 more answers
It is known that diskettes produced by a cer- tain company will be defective with probability .01, independently of each other.
zheka24 [161]

Answer:

1.27%

Step-by-step explanation:

To solve this problem, we may consider a binomial distribution where a customer can either accept or reject (and return) the diskette package.

Lets consider  some aspects:

1. From the formulation of the exercise we know that a package is accepted if it has at most 1 defective diskette. So our event A is defined as:

A = 0 or 1 defective diskette

2. The probability of a diskette being defective is 0.01

3. Each package contains 10 diskettes.

If X is defined as number of defective diskettes in the package, the probability of X is given by a binomial distribution with probability 0.01 and n=10

X ~ Bin(p=0.01, n=10)

Let us remember the calculation of probability for the binomial distribution:

P(X=x)=nCx*p^{x}*(1-p)^{(n-x)} with x = 0, 1, 2, 3,…, n

Where

n: number of independent trials

p: success probability  

x: number of successes in n trials

In our case success means finding a defective diskette, therefore

n=10

p=0.01

And for x we just need 0 or 1 defective diskette to reject the package

Hence,

P(X=x)=10Cx*0.01^{x}*(1-0.01)^{(10-x)} with x = 0, 1

So,

P(A)=P(X=0)+P(X=1)

P(A)=10C0*0.01^{0}*(1-0.01)^{(10-0)} + 10C1*0.01^{1}*(1-0.01)^{(9)}

P(A)=0.99^{10}+10*0.01*0.99^{9}

P(A)=0.9957

Now, because we have 3 packages and we might reject just 1 of them, we can find this probability like this:

3*(1-P(A))*P(A)*P(A) = (1-0.9957)*0.9957*0.9957=0.0127

Finally, we have that the probability of returning exactly one of the three packages is 1.27%

3 0
3 years ago
Use logarithmic properties and the fact that ln(2) ≈ 0.69 and ln(3) ≈ 1.10 to approximate the value of each of the
leva [86]

Answer:

The answer is 0.97

Step-by-step explanation:

Hi, we need to use the log properties taking into account that Ln(2) is aprox. 0.69 and Ln(3) is aprox. 1.10. I think you can understand better as we solve it, so here it goes.

Ln(\frac{8}{3} )=Ln(8)-Ln(3)

Since:

8=2^{3}

Ln(2^{3} )-Ln(3)

Then

3Ln(2)-Ln(3)

Now, we have everything where we want it, in terms of Ln(2) and Ln(3), now it is easy to solve.

3(0.69)-1.10

2.07-1.10=0.97

Best of luck.

5 0
3 years ago
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