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3 years ago

What is Quadratic inequality

1 answer:

7 0

Quadratic in equality is quadratic function that is compared to another function like: x^2+4x-1<2x-3. the answer for x must comply to both sides.

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260 years equals:

uranmaximum [27]

It would have to be letter D my guy, if you know what centuries and decades are this is easy

6 0

3 years ago

Read 2 more answers

Luanda wants to buy a box of cereal. Which box has the lowest cost per ounce? Group of answer choices 20-oz box for $3.20 10-oz

marin [14]

Answer: 15-oz for 2.25

3.20÷20= 0.16

1.70÷10= 0.17

2.25÷15= 0.15

2.72÷16= 0.17

I hope this helps:

3 0

2 years ago

Write the equation of the line described in point-slope form. Then, change to Standard Form. Contains points (3/2,-1/2) and (-1/

larisa [96]

Slope point form :
To put in slope point form, label any of the points as either X1,y1 and X and y, then plug in those values into the following equation form.
Y - y1 = m(X-X1)

But before, we must solve for the m value or slope.
M = y2-y1/x2-X1
M = 5/2 - -1/2 / -1/2 - 3/2.
M = 5/2 + 1/2 / -(1/2+3/2)
M = 6/2 / -(4/2)
M = 3/-2

Now we can place it in slope point and also in standard form of a line.

Y-y1 = m(X -X1)

Y - -1/2 = -3/2(X - 3/2)

Y + 1/2 = -3/2(X - 3/2)

This is in slope point form.

Y + 1/2 = -3/2x + 9/4
Y + 1/2 - 1/2 = -3/2x + 9/4 - 1/2
1/2 = 2/4
Y = -3/2x + 7/4
-3/2x = -6/4x
Y = -6/4x + 7/4
Y • 4 = 4( -6/4 X + 7/4)
4y = -6x + 7
4y + 6x = -6x + 6x +7

6x + 4y = 7

This is in standard form. If you have any questions of the steps just ask.

4 0

2 years ago

Which is an equation for the line shown?<br> A) x=2<br> B) y=2<br> C) x=-2<br> D) y=-2

Studentka2010 [4]

Answer:

A) x=2

Step-by-step explanation:

7 0

2 years ago

Maths functions question!!

Marina86 [1]

Answer:

5) DE = 7 units and DF = 4 units

6) ST = 8 units

$\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units$

8) x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

$f(x)=-x+3$

$g(x)=x^2-9$

A = (3, 0) and C = (-3, 0)

Points A and D are the <u>points of intersection</u> of the two functions.

To find the x-values of the points of intersection, equate the two functions and solve for x:

$\implies g(x)=f(x)$

$\implies x^2-9=-x+3$

$\implies x^2+x-12=0$

$\implies x^2+4x-3x-12=0$

$\implies x(x+4)-3(x+4)=0$

$\implies (x-3)(x+4)=0$

Apply the zero-product property:

$\implies (x-3)= \implies x=3$

$\implies (x+4)=0 \implies x=-4$

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

$\implies f(-4)=-(-4)=7$

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

To find point S, substitute the x-value of point T into function g(x):

$\implies g(4)=(4)^2-9=7$

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

$\implies ST=y_S-y_T=7-(-1)=8$

Therefore, ST = 8 units.

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x. To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

$\implies f(x)-g(x)=QR$