Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Answer:the answer is 44
Step-by-step explanation: cuz 40 divided by 90%= 44
Answer:
-1,080 + (-8)(11)
Step-by-step explanation:Well for one it has to be -1,080 becuase it already starts as a neagtive. So the answer has to -1,080 + (-8)(11) becuase you adding/mutpilying 8 x 11
6 to 5, 12 to 10, 18 to 15, 24 to 20, x to 25
Let's take a look at x/25 ratio, which has to be equal 6/5.
The answer is 30 inches.
0 is most likely the answer. considering you didn’t add a picture or anything like that.
