Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
Greatest error is half smallest measuring unit. It's measured to 0.1 cm , half that is 0.05 cm answer D.
Answer: Choice A) subtracting; subtractingThe goal is to find the legs of the right triangle, so you can find the hypotenuse. The hypotenuse is the distance between the two points. See the attached image.
1.) False
2.) True
1.) a dotted line infers that any ordered pair that comes after the line is true. Ordered pairs that fall on the line will falsify the inequality.
2.) With solid line graphed inequalities, and ordered pair on the line OR in the shaded region makes the inequality true.
