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katen-ka-za [31]
3 years ago
14

Which is the correct classification of sqrt 32

Mathematics
2 answers:
zubka84 [21]3 years ago
5 0

Answer:

The answer is A, irrational number and non repeating decimal

Step-by-step explanation:

I got it correct on edg

labwork [276]3 years ago
4 0

Answer:

irrational number, nonrepeating decimal

Step-by-step explanation:

You might be interested in
Find the product (8/6n-4)(9n^2-4)
Leokris [45]

Answer:

4(3n+2) or 12n+8

Step-by-step explanation:

Given expression is:

(\frac{8}{6n-4})(9n^{2}-4)

The numerator of the fraction will be multiplied with 9n^2- 4

So, Multiplication will give us:

=\frac{8(9n^2-4)}{6n-4}

We can simplify the expression before multiplication.

The numerator will be broken down using the formula:

a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}

We can take 2 as common factor from denominator

=\frac{8(3n-2)(3n+2)}{2(3n-2)}\\After\ cutting\\= 4(3n+2)

Hence the product is 4(3n+2) or 12n+8 ..

6 0
3 years ago
Can someone help me please?
ANTONII [103]

9514 1404 393

Answer:

  \textsf{B.}\ \ 6x-1+\dfrac{-11x+8}{x^2+3}

Step-by-step explanation:

See the attachment for the working out of the long division.

8 0
2 years ago
Help me pls working on quizizz :(
nexus9112 [7]

here your answer mate

3.25

hope it helps ☺️✌️

8 0
3 years ago
Read 2 more answers
If two parallel planes are cut by a third plane, then the lines of intersection are _________.
maxonik [38]
<span>If two parallel planes are cut by a third plane, then the lines of intersection are parallel and cannot intersect one another.</span>
6 0
3 years ago
Read 2 more answers
What is the probability that a randomly selected contestant won a prize, given that the contestant was female write the probabil
pantera1 [17]

We have given the table of number of male and female contestants who did and did not win prize

The probability that a randomly selected contestant won prize given that contestant was female is

P(contestant won prize / Contestant was female)

Here we will use conditional probability formula

P(A/B) = \frac{P( A and B)}{P(B)}

Let Event A = selected contestant won prize and

event B = selected contestant is famale

Then numerator entity will

P(A and B) = P(Contestant won prize and Contestant is female)

= Number of female contestant who won prize / Total number of contestant

= 3 /(4+9+3+10)

= 3 / 26

P(A and B) = 0.1153

P(B) = P(contestant is female )

= Number of female contestant / Total number of contestants

= (3+10) / 26

P(B) = 0.5

Now P(A / B) = \frac{P( A and B)}{P(B)}

= 0.1153 / 0.5

P(A / B) = 0.2306

The probability that randomly selected contestant won prize given that contestant is female is 0.2306

Converting probability into percentage 23.06%

The percentage that randomly selected contestant won prize given that contestant is female is 23%

3 0
3 years ago
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