Question

What is the probability that a randomly selected contestant won a prize, given that the contestant was female write the probability as a percent please help

Answer 1

We have given the table of number of male and female contestants who did and did not win prize

The probability that a randomly selected contestant won prize given that contestant was female is

P(contestant won prize / Contestant was female)

Here we will use conditional probability formula

P(A/B) = $\frac{P( A and B)}{P(B)}$

Let Event A = selected contestant won prize and

event B = selected contestant is famale

Then numerator entity will

P(A and B) = P(Contestant won prize and Contestant is female)

= Number of female contestant who won prize / Total number of contestant

= 3 /(4+9+3+10)

= 3 / 26

P(A and B) = 0.1153

P(B) = P(contestant is female )

= Number of female contestant / Total number of contestants

= (3+10) / 26

P(B) = 0.5

Now P(A / B) = $\frac{P( A and B)}{P(B)}$

= 0.1153 / 0.5

P(A / B) = 0.2306

The probability that randomly selected contestant won prize given that contestant is female is 0.2306

Converting probability into percentage 23.06%

The percentage that randomly selected contestant won prize given that contestant is female is 23%