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irina1246 [14]
3 years ago
9

Which word does NOT belong with the others? A. triangle B. circle C. oval D. sphere

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

A triangle because the other shapes are to do with circles.

Answer A.

Phoenix [80]3 years ago
6 0

Answer:

A triangle

Step-by-step explanation:

If you slice open all of these shapes you will see a circle except the triangle.

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If 9 less than 6 times a number lies between 31 and 37, what is the number
rjkz [21]

Answer:

7

Step-by-step explanation:

6x6=36

7x6=42

8x6=48

36-9=25 thus it isn't possible because it's not between 31 and 37. 48-9=39 hence also not possible. However for 42, it is defintely possible. Thus answer is 7

8 0
3 years ago
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Determine if the following triangle is a right triangle or not using the Pythagorean Theorem Converse. Triangle with side length
seraphim [82]

Answer:

A right triangle is a triangle in which one of the angles is a 90∘ angle. The "square" at the vertex of the angle indicates that it is 90 degrees. A triangle can be determined to be a right triangle if the side lengths are known.

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3 years ago
Given that E is the universal set and that A and B are subsets of E. simplify An(B-A)​
julsineya [31]

Answer:

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5 0
3 years ago
An equilateral triangle measures 3½ inches on one side. What is the perimeter of the triangle?
VLD [36.1K]
Since it's an equilateral triangle, all of the angles are the same. Since its perimeter we just need to add. So 3.5+3.5+3.5= 10.5
So the answer is 10.5
6 0
3 years ago
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Which of the following are solutions to the equation below?
scoundrel [369]

Answer:

The correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

Step-by-step explanation:

Given the expression

x^2+10x+25=8

Subtract 25 from both sides

x^2+10x+25-25=8-25

Simplify

x^2+10x=-17

Add 25 or 5² to both sides

x^2+10x+5^2=8

as

x^2+10x+5^2=\left(x+5\right)^2

so the expression becomes

\left(x+5\right)^2=8

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

solve

x+5=\sqrt{8}

Subtract 5 from both sides

x+5-5=2\sqrt{2}-5

x=2\sqrt{2}-5

solve

x+5=-\sqrt{8}

Subtract 5 from both sides

x+5-5=-2\sqrt{2}-5

x=-2\sqrt{2}-5

Therefore, the solution to the equation

x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5

Hence, the correct options for the solution values are:

  • x=2\sqrt{2}-5
  • x=-2\sqrt{2}-5

6 0
3 years ago
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