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defon
4 years ago
5

A dinner order at a restaurant consists of a salad with dressing, an entrée, and three sides. The menu offers a salad with your

choice of ranch, balsamic vinegar, or Italian dressing; a choice of entrée from catfish, roast beef, meat loaf, or pork chops; and, as sides, fried okra, corn, black-eyed peas, French fries, rice, mashed potatoes, pinto beans, green beans, or squash. How many possible dinner orders are available at the restaurant
Mathematics
2 answers:
Setler [38]4 years ago
7 0

Answer:

Imma try my best :)

ranch choices:

balsamic, vinegar, or Italian dressing

= 3

choice of entrée:

catfish, roast beef, meat loaf, or pork chops

= 4

Choices for sides

fried okra, corn, black-eyed peas, French fries, rice, mashed potatoes, pinto beans, green beans, or squash.

=9

Add all of the numbers together: 3 + 4 + 9 = 16

= 16 is the amount of choices, Take the amount of total choices and options in general (entrée,side,ranch) and divide.

= 5.33

(sorry if this answer s incorrect, This is a lot of words to take in)

Gemiola [76]4 years ago
5 0

Answer:

1008 possible dinner orders

Step-by-step explanation:

There are 3 possible salads, 4 possible entrees, and 9 possible sides.

Each dinner has 1 salad, 1 entree, and 3 sides.

Using combinations,

C(3,1) * C(4,1) * C(9,3) = 3 * 4 * 84 = 1008

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