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olga2289 [7]
3 years ago
5

Trisha ran 10 km in 2.5h. Jason ran 7.5 km in 2h. Olga ran 9.5 km in 2.25h. Who had the fastest average speed.

Mathematics
1 answer:
vlada-n [284]3 years ago
4 0

Hello!

10 km in 2.5h.

2,5h = 150mn

150mn -> 10km

1 mn -> 10/150

60mn -> (10*60)/150

=>4km/h

Jason ran 7.5 km in 2h.

7,5 /2 =3,75

=> 3,75km/h

Olga ran 9.5 km in 2.25h.

2,25h = 120 + 0,25 * 60 =>135mn

135mn -> 9,5km

1mn -> 9,5/ 135

60mn -> (9,5*60)/ 135 =>4,22km/h

Who had the fastest average speed.: <u>Olga </u>

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Assuming the following problem: "In Hamilton County, Ohio the mean number of days needed to sell a home is 86 days (Cincinnati Multiple Listing Service, April, 2012). Data for the sale 40 of homes in a nearby county showed a sample mean of 80 days with a sample standard deviation of 20 days. Conduct a hypotheses test to determine whether the mean number of days until a home is sold is different than the Hamilton county mean of 86 days in the nearby county. "

1) Data given and notation    

\bar X=80 represent the sample mean

s=20 represent the sample standard deviation

n=40 sample size    

\mu_o =86 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)    

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t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

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If we compare the p value with a significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, so there is not enough evidence to conclude that the mean for the data is significantly different from 86 days.    

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