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prisoha [69]
3 years ago
7

Trains headed for destination A arrive at the train station at 15-minute intervals tarting at 7am, where as trains headed for de

stination B arrive at 15-minute intervals tarting at 7:05am. (a) If a certain passenger arrives at the station at a time uniformly distributed between 7 and 8am, and then gets on the first train that arrives, what proportion of time does he or she go to destination A? (b) What if the passenger arrives at a time uniformly distributed between 7:10am and 8:10am?
Mathematics
1 answer:
grandymaker [24]3 years ago
8 0

Answer: a.) 2/3 ; b.) 7/12

Step-by-step explanation:

Given the following details :

Destination A trains arrives at station at 15 minutes interval starting from 7am

Destination B trains arrives at station at 15 minutes interval starting from 7.05am

A.) if a passenger arrives at station uniformly between 7am and 8am and gets on first train. What proportion of time does the passenger leave from destination A?

To leave for destination A. The passenger has to arrive before train to A departs and after train to B leaves.

Train to B leaves, starting at at 7.05 a.m and at interval of 15 minutes

Train to A leaves at 7.00 am and at interval of 15 minutes.

Therefore,

(Train B departs - train A arrives) (between 7 to 8am)

(7.05 - 7.15) + (7.20 - 7.30) + (7.35 - 7.45) + (7.50 - 8.00) = 40 minutes

Total time = 7.00 - 8.00 = 60 minutes

(40 ÷ 60) = 2/3 or 0.667

B.) If passenger arrives uniformly between 7.10am - 8:10am

(7.10 - 7.15) + (7.20 - 7.30) + (7.35 - 7.45) + (7.50 - 8)

5 + 10 + 10 + 10 = 35

35/60 = 7/12 or 0.583

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Step-by-step explanation:

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LiRa [457]
For each, you'll use the slope formula 
m = (y2-y1)/(x2-x1)

For function f, you'll use the two points (1,6) and (2,12) since x ranges from x = 1 to x = 2 for function f

The slope through these two points is 
m = (y2-y1)/(x2-x1)
m = (12-6)/(2-1)
m = 6/1
m = 6

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For function g, you'll use (2,4) and (3,20)

The slope through these two points is
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m = (20-4)/(3-2)
m = 16/1
m = 16

-------------------------------------------

For function h, you'll use (0,-6) and (2,-18). The y coordinates can be found by plugging in x = 0 and x = 2 respectively into h(x)

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6 0
3 years ago
Mehwish's temperature at 9:00 .. Was 97.2 ℉. At 4:00 .. Her temperature was risen to 99 ℉. By how many degrees did her temperatu
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Answer:

1.8° F

Step-by-step explanation:

Given that:

Mehwish's temperature at 9:00 = 97.2°F

Mehwish's temperature at 4:00 = 99°F

The degree rise in Mehwish's temperature is :

(Mehwish's temperature at 4:00 - Mehwish's temperature at 9:00)

(99°F - 97.2°F)

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4 0
2 years ago
(1.)What is the value of 35−3m , when m = 4?
Len [333]
(1.) 35-3m
m= 4

35-3m
= 35-3(4)
= 35-12 (do the multiple/division first before doing the addition/subtraction)
= 23

C. 23

(2.) 1 + x ÷ 5
x = 80

1 + x ÷ 5
= 1+80÷5
= 1+16
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(3.) mx-y
m=5, x=3, and y=8

mx-y
= 5(3)-8
= 15-8
= 7

(4.) 3a+15+bc−6
a=7, b=3, and c=15

3a+15+bc-6
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= 21+15+45-6
= 75
4 0
3 years ago
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