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alisha [4.7K]
3 years ago
15

What is the answer for 5/6 divided by 1 and 1/2

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
4 0
The answer is 5/6 divided by 1 is 5/6
lora16 [44]3 years ago
3 0
10/18 or 5/9. To get this you first have to make your mixed number into a fraction. 1 and 1/2 is = to 3/2 so 5/6 * 2/3 = 10/18
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Step-by-step explanation:

The equation representing a proportional relationship is

y = kx ← k is the constant pf proportionality

Here k = 6 , then

y = 6x ← equation of proportion

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Write the function for each graph below.​
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Find the surface area of a cylinder with a diameter of 18 and a height of 32. Use 3.14 for π. Round your answer to the nearest t
Ksenya-84 [330]

Answer: a = 2,315.5

Step-by-step explanation:

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7 0
3 years ago
I need help with these
rewona [7]
Also 8 i believe not sure though
8 0
3 years ago
2. Suppose that you are looking for a student at your college who lives within five miles of you. You know that 55% of the 25,00
svlad2 [7]

Using the binomial distribution, it is found that:

a) There is a 0.0501 = 5.01% probability that you need to contact four people.

b) You expect to contact 1.82 students until you find one who lives within five miles of you.

c) The standard deviation is of 1.22 students.

d) There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.

e) It is expected that 2.75 students live within five miles of you.

For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 55% of the students live within five miles of you, thus p = 0.55.

Item a:

This probability is P(X = 0) when n = 3(none of the first three living within five miles of you) multiplied by 0.55(the fourth does live within five miles), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.55)^{0}.(0.45)^{3} = 0.091125

p = 0.091125(0.55) = 0.0501

0.0501 = 5.01% probability that you need to contact four people.

Item b:

The expected number of trials in the binomial distribution until q successes is given by:

E = \frac{q}{p}

In this problem, p = 0.55, and 1 trial, thus q = 1, hence:

E = \frac{1}{0.55} = 1.82

You expect to contact 1.82 students until you find one who lives within five miles of you.

Item c:

The standard deviation of the number of trials until q successes are found is given by:

S = \frac{\sqrt{q(1 - p)}}{p}

Hence, since q = 1, p = 0.55:

S = \frac{\sqrt{0.45}}{0.55} = 1.22

The standard deviation is of 1.22 students.

Item d:

This probability is P(X = 3) when n = 5, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.55)^{3}.(0.45)^{2} = 0.3369

There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.

Item e:

The expected value of the binomial distribution is:

E(X) = np

Hence, since n = 5, p = 0.55:

E(X) = 5(0.55) = 2,75

It is expected that 2.75 students live within five miles of you.

A similar problem is given at brainly.com/question/25343741

7 0
3 years ago
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