I´m pretty sure that the terms would just be 3, 4, and 5. It depends what kind of problem it is.
The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
Answer:
C
Step-by-step explanation:
Answer:
35
Step-by-step explanation:
4 x 15 = 60
-4 x 5 = - 20
-1 x 5 = -5
60 - 20 - 5 = 35