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Kisachek [45]
3 years ago
14

Which equation could be used to solve this problem?

Mathematics
1 answer:
timama [110]3 years ago
8 0
The correct answer is B
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Divide the difference of 18 and 3 by the sun of 1 and 2​
NikAS [45]

Okay.

(18-3)/(1+2) = 15/3 = 5

answer: 5

4 0
3 years ago
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Find CD if C(0,3) and D(4,7)
weeeeeb [17]
C(0,3) \\
x_1=0 \\
y_1=3 \\ \\
D(4,7) \\
x_2=4 \\
y_2=7 \\ \\
\overset{\underline{\ \ \ \ }}{CD} =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(4-0)^2+(7-3)^2}= \\
=\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{16 \times 2}=4\sqrt{2} \\ \\
\boxed{\overset{\underline{\ \ \ \ }}{CD} = 4\sqrt{2}}
7 0
3 years ago
Write an equation of the line that passes through (2,-4) and (0,-4)
Arte-miy333 [17]

y = mx + b

To find the slope(m), you use the slope formula:

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

You plug in the points into the equation.

m = \frac{-4 - (-4)}{0 - 2}

m = \frac{-4+4}{0-2} = \frac{0}{-2} =0

The slope is 0

y = 0x + b

Any number multiplied by 0 is 0. So:

y = b

To find b, you plug in the y value of either of the points.

-4 = b

Your equation is:

y = -4 (This is a horizontal line)

5 0
3 years ago
Which of the following expressions is equivalent to a3 + b3?
lubasha [3.4K]
ANSWER
{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
{a}^{3}  + {b}^{3}
we must first expand
{(a + b)}^{3}
Then we rearrange to find the required expression.


So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

{(a + b)}^{3}  =  {a}^{3}  + 3 {a}^{2}b + 3a {b}^{2}   +  {b}^{3}


Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3ab (a+ b)





We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


(a + b)({(a + b)}^{2}  - 3ab ) =  {a}^{3}   +  {b}^{3}


We expand the bracket on the left hand side to get,

(a + b)( {a}^{2}  + 2ab +  {b}^{2}   - 3ab ) =  {a}^{3}   +  {b}^{3}


We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
5 0
3 years ago
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First five common multiples of 7and 20
gulaghasi [49]
The first 5 Multiples of 7<span> are 35, 70, 105, 140, 175
</span>The first 5<span> Multiples of </span>20<span> are: </span>20<span>, 40, 60, 80, 100
</span>
4 0
3 years ago
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