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olga nikolaevna [1]
3 years ago
10

D (t)=16t□2+96t+112 where t represents time in seconds

Mathematics
1 answer:
Luda [366]3 years ago
3 0
A.
the starting point is where t=0
d(0)=-16(0)^2+96(0)+112
D(0)=112
started from 112 feet


b. max height is vertex
for
y=ax^2+bx+c
the x value of the vertex is -b/2a

so
D(t)=-16t^2+96t+112
t value of vertex is -96/(2*-16)=3
it reaches after 3 seconds

C. simpliy evaluate D(t) for t=3
D(3)=-16(3)^2+96(3)+112
D(3)=-16(9)+288+112
D(3)=-144+400
D(3)=256
max height is 256ft
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A 14 foot ladder is placed against a wall. It is placed 5 feet from the base of the wall.
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c = 18.47

Step-by-step explanation:

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Jamal's deck is in the shape of a polygon and is shown on the grid below.(-8,6)(6,6)o[(-8, -4),(6,-4)What is the area of Jamal's
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Let;

A(-8,6) B(6,6) C(6, -4) D(-8, -4)

Let's find the length AB

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We will use the distance formula;

d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}

=\sqrt[]{(6+8)^2+(6-6)^2}=\sqrt[]{14^2+0}=14

Next, we will find the width BC

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x₁= 6 y₁=6 x₂=6 y₂=-4

substitute into the distance formula;

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Area = l x w

= 14 x 10

= 140 square units

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1 year ago
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