I believe your answer is b.
<h3>There are 76 nickels in jar</h3>
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "n" be the number of quarters
1 dime = $ 0.10
1 nickel = $ 0.05
There are 140 coins in the jar
Therefore,
d + n = 140
n = 140 - d ------- eqn 1
Lee has $10.20 in a jar that contains only nickels and dimes
Therefore,

0.1d + 0.05n = 10.20 -------- eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.1d + 0.05( 140 - d) = 10.20
0.1d + 7 - 0.05d = 10.20
0.05d = 3.2
Divide both sides by 0.05
d = 64
<em><u>Substitute d = 64 in eqn 1</u></em>
n = 140 - 64
n = 76
Thus there are 76 nickels in jar
Answer: 162
Step-by-step explanation:
So you will need to find the Markup. The original cost is $120.
- Divide the number by 100 is 1.2. $1.2 is 1% of the $120.
- Now times the number by 35. $1.2 x 35 is $42.
- Finally, add the number. 120 + 42 = 162.
I hope this is the answer you are looking for.
85 + 95 = 180$
So 150 - 180 = -30$ so she is 30 dollars in debt.
X+x-1+x-2=267
3x-3=267
3x=270
X=90 90+90-1+90-2=267
90+89+88=267
Three integers 88,89,90