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2 years ago

Can someone help me please!!!!

Mathematics

1 answer:

Softa [21]2 years ago

6 0

Answer:

step 1. DBE ~ ABC

step 2. (x + 5)/4 = (2x + x + 5)/(4 + 3)

step 3. ( x + 5)/4 = (3x + 5)/7

step 4. 7x + 35 = 12x + 20

step 5. 5x = 15

step 6. x = 3.

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Find the equation of a line that passes through the points (-2,-3) and (4,1)

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The equation of the line from give points is y = 2/3x - 5/3.

According to the statement

We have given that the two points which are (-2,-3) and (4,1)

And we have to find the equation of a line that passes through the given points.

So,For this purpose,

First, we need to determine the slope of the line. The slope can be found by using the formula:

$m = \frac{(y_2) -(y_1)}{(x_2) -(x_1)}$

Where

m is the slope and

Substituting the values from the points in the problem gives:

m = 1 + 3 /4 + 2

m = 4/6

m = 2/3.

And then

Now, we can use the point-slope formula to find an equation for the line. The point-slope formula states:

$y - (y_1) = m(x -x_1)$

Put the values in it then

y - (-3) = 2/3 (x-(-2))

y +3 = 2/3 (x +2)

3y + 9 = 2x + 4

3y - 2x = 4 -9

3y -2x = -5

3y = 2x - 5

y = 2/3x - 5/3.

So, The equation of the line from give points is y = 2/3x - 5/3.

Learn more about equation of the line here

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1 year ago

If you are choosing a single card from a standard deck of playing cards, what is

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Step-by-step explanation:

there are 4 suit with 13 cards each

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1 year ago

A kite flying in the air has an 7-ft line attached to it. Its line is pulled taut and casts a 5-ft shadow find the heights of th

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The height of the kite is 4.89 feet

Explanation

The length of the line attached to the kite=7 feet

The length of the shadow that is cast on the ground=5 feet

the system forms a right angled triangle where the taught string of the kite is the hypotenuse, the shadow is the base and the height of the kite above the ground is the height.

H=7 feet

b=5 feet

using pythagoras theorem

$h^2+b^2=H^2\\h^2=H^2-b^2\\h^2=7^2-5^2\\=49-25\\=24\\h=\sqrt{24\\} =2\sqrt{6} \\=4.89 feet$

The kite is 4.89 feet above the ground

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2 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

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Give two systems of equations that would be easier to solve by substitution than by elimination. Then give two systems that woul

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These techniques for elimination are preferred for 3rd order systems and higher. They use "Row-Reduction" techniques/pivoting and many subtle math tricks to reduce a matrix to either a solvable form or perhaps provide an inverse of a matrix (A-1)of linear equation AX=b. Solving systems of linear equations (n>2) by elimination is a topic unto itself and is the preferred method. As the system of equations increases, the "condition" of a matrix becomes extremely important. Some of this may sound completely alien to you. Don't worry about these topics until Linear Algebra when systems of linear equations (Rank 'n') become larger than 2.

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2 years ago