<h3>Explanation:</h3>
Any techniques that you're familiar with can be applied to polynomials of any degree. These might include ...
- use of the rational root theorem
- use of Descartes' rule of signs
- use of any algorithms you're aware of for finding bounds on roots
- graphing
- factoring by grouping
- use of "special forms" (for example, difference of squares, sum and difference of cubes, square of binomials, expansion of n-th powers of binomials)
- guess and check
- making use of turning points
Each root you find can be factored out to reduce the degree of the remaining polynomial factor(s).
Answer:
more than 90° or less than 180°
Answer:
(x-8)(x-2)
Step-by-step explanation:
factors of 16:
1 x 16
2 x 8
4 x 4
i'll select 2 and 8 as values because they can add up to 10
(x-8)(x-2)
i made them both negative so the middle term would be -10 but, when multiplied, would equal positive 16
Answer:
76
Step-by-step explanation:
All sides of a rhombus are equal. Set NR equal to RQ, solving for x. When you find x, plug it back into either equation to find PQ.
The answer is
<span>x+1</span>, <span>x+2</span>, <span>x+3</span>, <span>x+4</span> and <span>x+5</span>.
The sum of these six integers is 393 so we can write:
<span>x+x+1+x+2+x+3+x+4+x+5=393</span>
<span>6x+1+2+3+4+5=393</span>
<span>6x+15=393</span>
<span>6x+15−15=393−15</span>
<span>6x+0=378</span>
<span><span><span>6x</span>6</span>=<span>3786</span></span>
<span>x=63</span>
Because the first integer is 63 then the third would be <span>x+2</span> or <span>63+2=<span>65</span></span>
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<span><span>Hope its helps :)</span></span>
