Can someone help me figure out what is JK and LK

Mathematics

1 answer:

vivado [14]3 years ago

3 0

Answer:

JK = 10.524

LK = 21.065

Step-by-step explanation:

all angles in a triangle add up to 180, so angle K = 42.

law of sines states that $\frac{A}{sin(a)} =\frac{B}{sin(b)} = \frac{C}{sin(c)}$ , where capital letters are side lengths and lower case letters are the angles opposite their corresponding capital letter sides.

in this case:

$\frac{15}{sin(42)} = \frac{JK}{sin(28)}$ -----> JK = $\frac{15sin(28)}{sin(42)}$ = 10.524

and

$\frac{15}{sin(42)} = \frac{LK}{sin(110)}$ -----> LK = $\frac{15sin(110)}{sin(42)}$ = 21.065

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Alex787 [66]

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<u>Solution:</u>

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We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

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Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

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$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$