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3 years ago

What is the slope of the line that passes through the points (13,-8) and (-11,4)

Mathematics

1 answer:

pogonyaev3 years ago

3 0

Answer:

- $\frac{1}{2}$

Step-by-step explanation:

Find slope using the slope formula : $\frac{y2-y1}{x2-x1}$

Plug in the given points : $\frac{4- (-8)}{-11-13}$

Add the numbers : $\frac{12}{-11-13}$

Calculate the difference : $\frac{12}{-24}$

Reduce the fraction : - $\frac{1}{2}$

Solution : - $\frac{1}{2}$

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Equation of the line that is perpendicular to y= 1/8x -2 and goes through the point <br> (-2,-3)

larisa [96]

The answer to this equation is y=-8x-19

I hope this helps!!!!!!!!

7 0

3 years ago

Read 2 more answers

Please help. If you answer correctly and give an explanation I'll give you 5 stars, thanks, and brainliest.

timama [110]

The solution of the equation is $x=\frac{11}{7}$

Step-by-step explanation:

To simplify an equation of x

Simplify each side of the equation
Collect x in side and the numerical terms in the other side
Find the value of x

∵ The equation is $2x + \frac{1-x}{4}=3$

- Multiply all terms of the equation by 4 to cancel the denominator

of the 2nd term in the left hand side

∵ The equation is $4(2x) +4 (\frac{1-x}{4})=4(3)$

∴ 8x + (1 - x) = 12

∴ 8x + 1 - x = 12

- Add like terms

∴ (8x - x) + 1 = 12

∴ 7x + 1 = 12

- Subtract 1 from both sides

∴ 7x = 11

- Divide both sides by 7

∴ $x=\frac{11}{7}$

The solution of the equation is $x=\frac{11}{7}$

Learn more:

You can learn more about the solution of an equation in brainly.com/question/11306893

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3 0

3 years ago

What kind of angle pair do they create?

Bond [772]

Answer:

They create supplementary angle pairs.

Step-by-step explanation:

Supplementary angles add up to 180°.

8 0

3 years ago

Expand each expression

matrenka [14]

Answer:

Option B - $\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Step-by-step explanation:

Given : Expression $\ln(\frac{4y^5}{x^2})$

To find : Expand each expression ?

Solution :

Using logarithmic properties,

$\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B$

and $\ln (AB)=\ln A+\ln B$

Here, A=4y^5 and B=x^2

$\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}$

$\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2$

$\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2$

Using logarithmic property, $\logx^a=a\log x$

$\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Therefore, option B is correct.

3 0

3 years ago

Read 2 more answers

Solve the “and” compound inequality for –1 < 6x + 1 ≤ 13

ser-zykov [4K]

Answer:

-1/3 < x <(or equal to) 2

Step-by-step explanation:

Firstly divide your inequality into two separate inequalities...

1) -1 < 6x + 1...then solve for the first one..,which then gives you....;

-2 < 6x....which gives us our first solution (x > -1/3)

Then the second inequality

2) 6x + 1 <(or equal to) 13

which then gives you....,

6x <(or equal to) 12...which then gives our second solution...( x <(or equal to) 2)

Then combine the two solutions into a compound solution

-1/3 < x <(or equal to) 2

8 0

3 years ago