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4 years ago

12

Please answer this correctly

1 answer:

Paraphin [41]4 years ago

7 0

4000

as the first bit rounds to 5 and the second bit rounds to 800

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Find the derivative of the inverse function of the original function f(x)=(x+1)^3-5

____ [38]

Answer:

Step-by-step explanation:

let f(x)=y

$y=(x+1)^{3} -5\\flip ~x~and~y\\x=(y+1)^{3}-5\\(y+1)^{3}=x+5\\y=(x+5)^{\frac{1}{3} } -1\\or~f^{-1}(x)=(x+5)^{\frac{1}{3} } -1\\(f^{-1})'(x)=\frac{1}{3} (x+5)^{\frac{-2}{3} }$

4 0

3 years ago

The sum of 5 consecutive odd numbers is 135 what is the second number in this sequence

hoa [83]

Step-by-step explanation:

x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 135

5·x + 20 = 135

5·x = 115

x = 23

So the sequence is

23, 25, 27, 29, 31

The second number is 25.

Do you agree?

6 0

3 years ago

Simplify the expression. (Assume that all variables are positive.)<br><br> 108<br> 15d

andrezito [222]

25d because 10+15 = 25

7 0

3 years ago

Can anyone asnswer any of these questions?? I don't get this topic

saul85 [17]

Answer:

one

Step-by-step explanation:

one

8 0

3 years ago

The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

Answer:

The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

Here we see that

$4p=\frac{3}{2}$

$\therefore p=\frac{3}{8}$

Thus, finally we have the equation of the parabola in the standard form:

$\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}$

5 0

3 years ago