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sukhopar [10]
3 years ago
5

The difference between two numbers is 2790. If the smaller number is 3560, what is the other number?

Mathematics
1 answer:
8090 [49]3 years ago
4 0

Answer:

the other number is 6350

Step-by-step explanation:

given data

difference between two numbers = 2790

smaller number = 3560

to find out

the other number

solution

we consider here larger number  = x

smaller number  = y

so

so difference between two number is express as

difference between two number = x - y    ....................1

put here value and we get another number i.e large number

2790 = x - 3560

solve it we get

x = 6350

so the other number is 6350

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What is the length of BC , rounded to the nearest tenth?
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Step 1

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

AB^{2} =AD^{2}+BD^{2}

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AD=5\ units\\BD=12\ units

substitute the values

AB^{2}=5^{2}+12^{2}

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AB=13\ units

Step 2

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}

Step 3

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

cos(BAC)=cos (BAD)=\frac{5}{13}

cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}

\frac{5}{13}=\frac{AB}{AC}

\frac{5}{13}=\frac{13}{AC}

solve for AC

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Step 4

<u>Find the length of the segment DC</u>

we know that

DC=AC-AD

we have

AC=33.8\ units

AD=5\ units

substitute the values

DC=33.8\ units-5\ units

DC=28.8\ units

Step 5

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

BC^{2} =BD^{2}+DC^{2}

we have

BD=12\ units\\DC=28.8\ units

substitute the values

BC^{2}=12^{2}+28.8^{2}

BC^{2}=973.44

BC=31.2\ units

therefore

<u>the answer is</u>

BC=31.2\ units

8 0
3 years ago
Read 2 more answers
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