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LUCKY_DIMON [66]
3 years ago
15

Y=(?,?) x=(?,?) determine the intercept of the line

Mathematics
2 answers:
drek231 [11]3 years ago
8 0
Xintercept (125,0)
Yintercept (0,275)
Oksanka [162]3 years ago
7 0

Answer:

\boxed{\text{(125,0) and 0,275)}}

Step-by-step explanation:

An intercept is the point at which a line crosses an axis.

We have x- and y-axes, so we have x- and y-intercepts.

x-Intercept

The x-intercept is half-way between 100 and 150.

The two values are 50 units apart. Half-way would be 25 units between them.

The x-intercept is at x = 100 + 25 = 125 or (125,0)

y-Intercept

The y-intercept is half-way between 250 and 300.

Half-way between the two points is 275 units.

The y-intercept is at y = 275  or (0, 275)

\text{The intercepts are at }\boxed{\textbf{(125,0) and 0,275)}}

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Write an equation for the line that passes through the points (-1,-12) and (4,8)​
Aleks [24]

Answer:

y = 4x - 8

Step-by-step explanation:

(-1, -12) & (4, 8)

First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(8 - (-12)) / (4 - (-1))

Simplify the parentheses.

= (8 + 12) / (4 + 1)

= (20) / (5)

Simplify the fraction.

20/5

= 4

This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.

y = 4x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (4, 8). Plug in the x and y values into the x and y of the standard equation.

8 = 4(4) + b

To find b, multiply the slope and the input of x(4)

8 = 16 + b

Now, subtract 16 from both sides to isolate b.

-8 = b

Plug this into your standard equation.

y = 4x - 8

This is your equation.

Check this by plugging in the other point you have not checked yet (-1, -12).

y = 4x - 8

-12 = 4(-1) - 8

-12 = -4 - 8

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Your equation is correct.

Hope this helps!

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Answer:

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