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BabaBlast [244]
2 years ago
10

In triangle ABC, m∠ABC = (4x – 12)° and m∠ACB = (2x + 26)°. Yin says that if x = 19, the triangle must be equilateral. Is he cor

rect? Justify your answer
Mathematics
2 answers:
spin [16.1K]2 years ago
5 0
He is not correct.  If this is to be an equilateral triangle then all the angles must be the same measure.  That means that 180/3 = 60°.  They all have to equal 60°.  If one of the angles measures 4x-12, then 4x-12=60.  Solving for x, we will add 12 to both sides to get 4x=72.  x here is 18.  For the other angle measuring 2x+26, we would do the same.  2x+26=60.  Subtract 26 from both sides to get 2x= 34 and x = 17.  He was way off.
andreyandreev [35.5K]2 years ago
4 0

No, Yin is not correct. If  x = 19, the measure of angle ABC = 4(19) – 12 = 64. Therefore, the two base angles measure 64°. An equilateral triangle is quadrangular, so each angle would have to measure 60° because there are 180° in a triangle.

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Identify the graph of 3x^2+y^2=9 for T(-1,3) and write an equation of the translated or rotated graph in general form.
Archy [21]

ANSWER

D. Ellipse;

3{x}^{2}  +{y}^{2}  + 6x   - 6y + 3= 0

EXPLANATION

The given equation is

3 {x}^{2}  +  {y}^{2}  = 9

Dividing through by 9 gives

\frac{ {x}^{2} }{ 3}  +  \frac{ {y}^{2} }{9}  = 1

This is the equation of an ellipse centered at the origin.

If this ellipse has been translated, so that its center is now at (-1,3), then the equation of the translated ellipse becomes

\frac{ {(x + 1)  }^{2} }{ 3}  +  \frac{ {(y - 3)}^{2} }{9}  = 1

We multiply through by 9 to get,

3 {(x + 1)}^{2}  +  {(y - 3)}^{2}  = 9

Expand to obtain;

3( {x}^{2}  + 2x + 1) +  {y}^{2}  - 6y + 9 = 9

Expand to obtain;

3{x}^{2}  + 6x + 3+  {y}^{2}  - 6y + 9 = 9

Regroup and equate to zero to obtain;

3{x}^{2}  +{y}^{2}  + 6x   - 6y + 3= 0

8 0
3 years ago
Read 2 more answers
Let R be the triangular region in the first quadrant with vertices at points (0,0), (a,0), and (0,b), where a and b are positive
Salsk061 [2.6K]

Answer:

volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( \frac{-b}{a}x + b )² dx

Step-by-step explanation:

Given the data in the question and as illustrated in the image below;

R is in the region first quadrant with vertices; 0(0,0), A(a,0) and B(0,b)

from the image;

the equation of AB will be;

y-b / b-0 = x-0 / 0-a

(y-b)(0-a) = (b-0)(x-0)

0 - ay -0 + ba = bx - 0 - 0 + 0

-ay + ba = bx  

ay = -bx + ba

divide through by a

y = \frac{-b}{a}x + ba/a

y = \frac{-b}{a}x + b

so R is bounded by  y = \frac{-b}{a}x + b and y =0, 0 ≤ x ≤ a

The volume of the solid revolving R about x axis is;

dv = Area × thickness

= π( Radius)² dx

= π ( \frac{-b}{a}x + b )² dx

V = π ₀∫^a ( \frac{-b}{a}x + b )² dx

Therefore,  volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( \frac{-b}{a}x + b )² dx

6 0
2 years ago
Rounding 255 to the nearest 5percent
Flauer [41]

Answer:

It would be 260

Step-by-step explanation:

Hope this helps :))

5 0
2 years ago
How do U dooo this ???
Sloan [31]
Put 10% into a fraction 10/100 = 1/10. Now times 88 KG by 1/10 and you should have the answer.
10% = 10/100 = 1/10

88/1 X 1/10 = 1/20
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3 years ago
There are 5 green jelly beans, 7 red jelly beans and 8 yellow jelly beans. What percent of the jelly beans are red?
s2008m [1.1K]

Answer: 35%

Step-by-step explanation:

8 + 5 + 7 = 20

50% = 10

25% = 5

10% = 2

5% = 1

25% + 10% = 5+2

35% = 7

5 0
3 years ago
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