(x^4)^1/2(x^6)^(-1/3)

1 answer:

3 0

To get the answer you split the problem in half and work each part separately

(x^4)^1/2 (x^6)^(-1/3)

then you multiply the exponents

x^2 1/x^2

and then you can cross multiply by converting x^2 into a fraction

and your answer is 1

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What is the product of 2x2 – 3xy + y2 and 2x – 4y?

dybincka [34]

Answer:

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

Step-by-step explanation:

Given:

Product of 2x^2 – 3xy + y^2 and 2x – 4y

Product means multiplication

(2x^2 – 3xy + y^2) (2x – 4y)

Open the bracket

= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3

Simplify the like terms

= 4x^3 - 14x^2y + 14xy^2 - 4y^3

The answer is

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

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Answer:

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Step-by-step explanation:

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We will use z-score formula to solve our given problem.

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