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2 years ago

15

PLS HELP WILL MARK YOU BRIANLIEST

2 answers:

Rasek [7]2 years ago

8 0

Answer:

Area=210

perimeter=66

Step-by-step explanation:

A=a+b(h)/2

P=a+b+c+d

Citrus2011 [14]2 years ago

4 0

Answer:

Step-by-step explanation:

$A=\frac{a+b}{2}h\\ =\frac{18+24}{2}*10\\ =210m^2$ (AREA)

$P=a+b+c+d\\=18+24+12+12\\=66m$ (PERIMETER)

Perimeter is just the outside lengths

Area is the whole inside area which is larger than the perimeter

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What is the slope of the line? <br><br> A. -5 <br><br> B. 1/5<br><br> C. 5 <br><br> D. -1/5

jeka57 [31]

Answer:

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Step-by-step explanation:

gate66

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2 years ago

Find the value of x in each case. Give reasons to justify your solutions! NEEDED ASAP

Mashcka [7]

Answer:

<em>( x = 17° )</em>

Step-by-step explanation:

Consider the following steps;

$m< ZYW = 2x - Given,\\m< YXW = ( 3x - 5 ) - Given,\\m< XYW = 90 - Given,\\\\m< YXW + m< XYW + m< YWX = 180 - Sum of Angles in Triangle,\\( 3x - 5 ) + 90 + m< YWX = 180,\\3x - 5 + 90 + m< YWX = 180,\\3x - 5 + m< YWX = 90,\\m< YWX = 90 - 3x - 5,\\m< YWX = 85 - 3x,\\\\m< ZYW = m< YWX - Alternate Interior Angles,\\2x = 85 - 3x,\\5x = 85,\\Conclusion ; ( x = 17 degrees )$

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3 years ago

How many of the ways that 27 cents can be made using quarters, dimes, nickels, and pennies use an odd number of coins

Mama L [17]

I believe the answer is 13 ways to make 27 cents using Quarters, dimes, nickels, and pennies.

Step-by-step explanation:

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2 years ago

My question is what's <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7D%7B5%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B2.5%7D%20

Reptile [31]

Hi, I'd be glad to help you with this equation.

The answer is (x = 4)

Hope this helps.
Have a great day!

6 0

3 years ago

Will mark brainliest!!!plz helppp

muminat

Answer:

(5,-6)

Step-by-step explanation:

ONE WAY:

If $f(x)=x^2-6x+3$ , then $f(x-2)=(x-2)^2-6(x-2)+3$ .

Let's simplify that.

Distribute with $-6(x-2)$ :

$f(x-2)=(x-2)^2-6x+12+3$

Combine the end like terms $12+3$ :

$f(x-2)=(x-2)^2-6x+15$

Use $(x-b)^2=x^2-2bx+b^2$ identity for $(x-2)^2$ :

$f(x-2)=x^2-4x+4-6x+15$

Combine like terms $-4x-6x$ and $4+15$ :

$f(x-2)=x^2-10x+19$

We are given $g(x)=f(x-2)$ .

So we have that $g(x)=x^2-10x+19$ .

The vertex happens at $x=\frac{-b}{2a}$ .

Compare $x^2-10x+19$ to $ax^2+bx+c$ to determine $a,b,\text{ and } c$ .

$a=1$

$b=-10$

$c=19$

Let's plug it in.

$\frac{-b}{2a}$

$\frac{-(-10)}{2(1)}$

$\frac{10}{2}$

$5$

So the $x-$ coordinate is 5.

Let's find the corresponding $y-$ coordinate by evaluating our expression named $g$ at $x=5$ :

$5^2-10(5)+19$

$25-50+19$

$-25+19$

$-6$

So the ordered pair of the vertex is (5,-6).

ANOTHER WAY:

The vertex form of a quadratic is $a(x-h)^2+k$ where the vertex is $(h,k)$ .

Let's put $f$ into this form.

We are given $f(x)=x^2-6x+3$ .

We will need to complete the square.

I like to use the identity $x^2+kx+(\frac{k}{2})^2=(x+\frac{k}{2})^2$ .

So If you add something in, you will have to take it out (and vice versa).

$x^2-6x+3$

$x^2-6x+(\frac{6}{2})^2+3-(\frac{6}{2})^2$

$(x+\frac{-6}{2})^2+3-3^2$

$(x+-3)^2+3-9$

$(x-3)^2+-6$

So we have in vertex form $f$ is:

$f(x)=(x-3)^2+-6$ .

The vertex is (3,-6).

So if we are dealing with the function $g(x)=f(x-2)$ .

This means we are going to move the vertex of $f$ right 2 units to figure out the vertex of $g$ which puts us at (3+2,-6)=(5,-6).

The $y-$ coordinate was not effected here because we were only moving horizontally not up/down.

3 0

2 years ago