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Ksivusya [100]
3 years ago
8

What is the product of 2x2 – 3xy + y2 and 2x – 4y?

Mathematics
1 answer:
dybincka [34]3 years ago
8 0

Answer:

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

Step-by-step explanation:

Given:

Product of 2x^2 – 3xy + y^2 and 2x – 4y

Product means multiplication

(2x^2 – 3xy + y^2) (2x – 4y)

Open the bracket

= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3

Simplify the like terms

= 4x^3 - 14x^2y + 14xy^2 - 4y^3

The answer is

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

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Which of the following is equivalent to (5 /k) + ((k + 3) /(k + 5)) ?
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Did I do these two correctly?
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3 years ago
In the given figure, find ∠PQS, if∠PQR = 5x + 25 and∠SQR = 2x + 10.
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Answer:

∠PQS= 3(x +5)

Step-by-step explanation:

∠PQR = 5x + 25

∠SQR+∠PQS= 5x+25

∠PQS = ∠PQR-∠SQR

∠PQS= (5x + 25 )-(2x + 10)

∠PQS = 5x+25 -2x-10

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3 years ago
A number picked at random from the numbers 1 through 15 is prime. This "question" is on my study guide for Unit 6 Probability an
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Solution:

we are given that

A number picked at random from the numbers 1 through 15 is prime.

As we know the number between 1 and 15 which are primes are listed below

2,3,5,7,11,13.

Here total number of favourable outcomes are 6.

The numbers 1 through 15 are as below:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15.

Here total number of possible outcoes are 15.

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime=\frac{6}{15}=\frac{2}{5}=0.40

Hence the probability that if a number picked at random from the numbers 1 through 15 is prime is 0.4

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3 years ago
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