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Ksivusya [100]
3 years ago
8

What is the product of 2x2 – 3xy + y2 and 2x – 4y?

Mathematics
1 answer:
dybincka [34]3 years ago
8 0

Answer:

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

Step-by-step explanation:

Given:

Product of 2x^2 – 3xy + y^2 and 2x – 4y

Product means multiplication

(2x^2 – 3xy + y^2) (2x – 4y)

Open the bracket

= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3

Simplify the like terms

= 4x^3 - 14x^2y + 14xy^2 - 4y^3

The answer is

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

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3 years ago
Which classification describes AMNO with vertices M(2, -3), N(3, 1), and<br> 0(-3, 1)?
Sonja [21]

Answer:

Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points (x_1,y_1) and (x_2,y_2) is given by the expression,

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between M(2, -3) and N(3, 1) will be,

MN = \sqrt{(3-2)^2+(1+3)^2}

      = \sqrt{1+16}

      = \sqrt{17}

Distance between M(2, -3) and O(-3, 1),

MO = \sqrt{(2+3)^2+(-3-1)^2}

      = \sqrt{25+16}

      = \sqrt{41}

Distance between N(3, 1) and O(-3, 1),

NO = \sqrt{(3+3)^2+(1-1)^2}

      = 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

(\sqrt{41})^2=(\sqrt{17})^2+6^2

41 = 17 + 36

41 = 51

False.

Therefore, given triangle is not a right triangle.

Since, length of all sides are not equal, given triangle will be a scalene triangle.

Option D is the correct option.

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3 years ago
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Answer:

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Step-by-step explanation:

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3 0
2 years ago
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so, -x=1/3 -5/2

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3 years ago
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