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blagie [28]
3 years ago
6

Cumulative Preference stockholders receive $.90 per share. There are 40,000 shares. For the last four years no dividends have be

en paid. This year $170,000 is paid out in dividends. How much in dividends to Preferred Stockholders are still in arrears?
Business
1 answer:
Helen [10]3 years ago
4 0

Answer:

$10,000

Explanation:

Data provided in the question:

Dividend per share = $0.90

Number of shares = 40,000

Number of years for which dividend is not paid = 4 years

Dividend paid this year = $170,000

Now,

Dividend still in arrears

= ( Number of years × Shares × Dividend per share ) - Dividend paid this year

= [ ( 4 + 1 ) × 40,000 × $0.9 ] - [ $170,000 ]

= $180,000 - $170,000

= $10,000

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The statement that is not true of this ceremony is:

F. it is essentially about the individual rather than the community

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The focus of this communal rite of passage is not the individual but the community because during the rite, the sense of the individual is replaced by the sense of the community.  It instils in the initiates a sense that they are no longer individuals but members of the community with some rights and privileges.  Community values are communicated through a sophisticated system of beliefs and practices that affirm sacred cycles.

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A speed boat bought for $13,000 depreciates at 10% per annum compounded continuously. What is its value after 7 years? Round the
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9100

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2(10-24x)+y2evaluate the expression when x=3 and y=5
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your correct answers is 114


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By post or hand deliver is known as​
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As part of a major plant renovation project, the industrial engineering department has been asked to balance a revised assembly
ioda

Answer:

A)Minimum = 0.2 minutes

Maximum = 4.6 minutes

Cycle time = = 2 minutes per unit

B) Number of Stations = 3

D) the percentage of idle time for the assignment in decimal = 0.43

Explanation:

A) Operating output = 240 units per 8hours.

Converting to per hour, we get; 240/8 = 30 units per hour.

Minimum cycle time = longest task time

Maximum cycle time = sum of task times

Minimum = 0.2 minutes

Maximum = 0.2 + 0.4 + 0.2 + 0.4 + 1.2 + 1.2 + 1.0 = 4.6 minutes

Now, operational time(OT) is 8 hours a day. Converting that to minutes, we have =60x8 = 480 minutes

Cycle time(CT) = OT (per day) /desired output

Therefore, calculated cycle time = 480/240

= 2 minutes per unit

B) Number of stations = Maximum time / CT

= 4.6/2 = 2.3 which is approximately 3 stations

C) The task diagram is drawn in image 1 attached. Therefore, we can assign tasks based in the greatest number of following tasks as follows;

Task Number of following tasks

a 4

b 3

c 2

d 2

e 1

f 1

g 0

D) for the idle time from the assigned tasks in "c" above, from the "image 2" attached; the percentage of the idle time will be=

Total remaining time of tasks without remaining feasibility tasks/ {(number of these tasks) x(CT)}

Which gives percentage of idle time = (0.8 + 0.8 + 0.8 + 1.0)/{(4)x(2)}

= 3.4/8 = 42.5%

Since we are to convert to decimal,

= 0.425 approximately 0.43

4 0
3 years ago
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