Question

If G(x) = 3x+1, then G^-1(1) is?

Answer 1

 First you change x and y 

=> x = 3y - 5 

Then you solve for y: 

x+5 = 3y /:3 

y = g^(-1)(x) = (1/3)x + (5/3) 

Answer 2

Answer:

0

Step-by-step explanation:

We are given that

$G(x)=3x+1$

We have to find the value of $G^{-1}(1)$

To find the value of  $G^{-1}(1)$ we will find first $G^{-1}(x)$

Let $y=G(x)=3x+1$

$3x=y-1$

$x=\frac{1}{3}(y-1)$

Now, replace x by y and y replace by x

Then, we get

$y=\frac{1}{3}(x-1)$

Now, substitute $G^{-1}(x)=y$

$G^{-1}(x)=\frac{1}{3}(x-1)$

Now, substitute x=1

Then, we get

$G^{-1}(1)=\frac{1}{3}(1-1)=0$

Hence, the value of $G^{-1}(1)=0$