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3 years ago

6

Which equation can you solve to find the potential solutions to the equation log2x + log2(x – 6) = 4?

2 answers:

aliya0001 [1]3 years ago

6 0

the answer is option 3: x^2-6x-16=0

riadik2000 [5.3K]3 years ago

3 0

If the question is

$log_2(x)+log_2(x-6)=4$

which can be simplified to

$log_2(x(x-6))=4$

By the definition of log, $log_a(x)=y$ means $a^y=x$

=>

2^4=x(x-6)=x^2-6x

Simplify and solve for x

x^2-6x-16=0

(x+2)(x-8)=0

x=-2 or x=8

Since no answer choices are given, one of the equations in the above solution should appear in the answer choices.

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2 years ago

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3 years ago

PRACTICE ANOTHER A piece of wire 18 m long is cut into two pieces. One piece is bent into a square and the other is bent into an

sergejj [24]

Answer:

Step-by-step explanation:

We have the equations

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y = 54 / 15.93

= 3.39 metres

So x = (18-3(3.39) / 4 = 1.96.

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3 years ago

in Oklahoma the states sales tax is 7%.if James purchases a lawn mower then how much will James pay in states sales tax

Nimfa-mama [501]

Answer:

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2 years ago

Help asap my last question GIVING BRAINLIST!!!!

Alex

Answer:

1) $x < 0$

2) $x > 0$

3) $x < 10$

4) $x < -\frac{31}{55}$

5) $x \geq 0$

6) $x \geq -1$

Step-by-step explanation:

1) $-3 > 2x -3$

$2x- 3 < -3$

$2x - 3 + 3 < -3 +3$

$2x < 0$

$\frac{2x}{2} < \frac{0}{2}$

$x < 0$

2) $5 > -x + 5$

$-x + 5 < 5$

$- x + 5 -5 < 5 - 5$

$-x < 0$

$\frac{-x}{-1} < \frac{0}{-1}$

$x > 0$

3) $\frac{x}{5} -2 < 0$

$5 \times (\frac{x}{5} - 2 ) \times 5 < 0$

$x - 10 < 0$

$x -10 + 10 < 0 +10$

$x < 10$

4) $-5x + 11 > 31$

$-5x \cdot 11 < 31$

$-55x < 31$

$\frac{-55x}{-55} > \frac{31}{-55}$

$x < -\frac{31}{55}$

5) $\frac{1}{2}x - 4 \geq -4$

$\frac{1}{2}x -4 +4 \geq -4 +4$

$\frac{1}{2}x \geq 0$

$\frac{\frac{1}{2}x }{\frac{1}{2} } \geq \frac{0}{\frac{1}{2} }$

$x \geq 0$

6) $-4x + 2 \leq 6$

$-4x +2 - 2 \leq 6 -2$

$-4x < 4$

$\frac{-4x}{-4} \leq \frac{4}{-4}$

$x \geq -1$

6 0

3 years ago