Answer:
- The function is injective but nor surjective
Step-by-step explanation:
<u>We see that:</u>
<u>For any x₁ and x₂ ∈ N, </u>
- f(x) = x₁³ = x₂³ ⇒ x₁ = x₂, both are natural numbers
It it confirmed one-to-one, hence it is injective
<u>Check the surjectivity:</u>
f(x) = y ∈ N
<u>Let y = 2, then:</u>
Since x is not natural, the function is not surjective
Answer:
(x-2) (x+2)
Step-by-step explanation:
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Answer with Step-by-step explanation:
Since we have given that
a + b = c
and a|c
i.e. a divides c.
We need to prove that a|b.
⇒ a = mb for some integer m
Since a|c,
So, mathematically, it is expressed as
c= ka
Now, we put the above value in a + b = c.
So, it becomes,
a=mb, here, m = k-1
Hence, proved.
x = 6
The average of 4 numbers is 6, which means that (3 + 5 + 10 + x) all divided by 4 is 6. That means that 3 + 5 + 10 + x = 24, because 24/4 is 6.
18 + x = 24, subtract 18 from 24 to get x = 6.
3.174 is closer to 3.2 because, when rounding, 0.07 rounds up to 0.2.
