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4 years ago

Is non-traditional musical notation, like a body percussion composition, considered music?

Mathematics

1 answer:

kykrilka [37]4 years ago

5 0

Answer:

Music is an art form that means individuals can consider what is music to them.

Music in the dictionary describes music as any sound or voice that produces beauty or form. What shapes body percussion in any percussion would be therefore its form or beauty, to be considered music.

If it fails to provide that quality then it is just considered sound or at best notation to music like a short sound can provide would also be notation to music.

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Which line best represents the line of best fit for this scatter plot?

Lerok [7]

Answer: line R

Step-by-step explanation: because it crossing through the starting and ending points

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3 years ago

Dwight and Walt are building model cars. Dwight builds 7 fewer models than 4 times the number Walt builds.Dwight builds at most

Yuliya22 [10]

Answer: w lesser than or equal to 4

Step-by-step explanation:

Dwight and Walt are building model cars.

Let d = the number of models built by Dwight.

Let w = the number of models built by Walt.

Dwight builds 7 fewer models than 4 times the number Walt builds. This can be expressed as

d = 4w - 7 - - - - - - - - - 1

Dwight builds at most 9 models. This is expressed as

d lesser than or equal to 9

From equation 1

d = 4w - 7

4w = d + 7

w = (d+7)/4

Assuming Dwight built 9 models

w = (9+7)/4 = 4

Therefore,

Walt builds at most 4 models. It is expressed as

w lesser than or equal to 4

It is shown in the attached photo

7 0

3 years ago

Read 2 more answers

If David had $10. He shared $3 with Steve, $6 with Anderson. How much money does he have left?

elena-s [515]

The answer would be 1$. 10-3 (to steve) =7

7-6 (to anderson) = 1

5 0

3 years ago

A farmer outside of Clinton NC plants 20 plots of a new type of corn. The average yield for these plots is ī= 150 bushels per ac

bogdanovich [222]

Answer:

The 95% confidence interval is $(150\pm 8.8)$ .

Step-by-step explanation:

The information provided is:

$\bar x=150\\\sigma = 20\\n=20$

The critical value for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the margin of error as follows:

$MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}$

$=1.96\times\frac{20}{\sqrt{20}}\\\\=1.96\times 4.47214\\\\=8.7653944\\\\\approx 8.8$

Then the 95% confidence interval is:

$CI=\bar x\pm MOE$

$=150\pm 8.8$

Thus, the 95% confidence interval is $(150\pm 8.8)$ .

5 0

3 years ago

Twenty-five samples of 100 items each were inspected when a process was considered to be operating satisfactorily. In the 25 sam

notsponge [240]

a) The estimate of the proportion of defectives when the process is in control is 0.054

b) The standard error of the proportion if the sample size is 100 is 0.0226.

c) The upper control limit is 0.1218 and the lower control limit is 0 (since LCL < 0 and p > 0, we can write LCL = 0).

<h3>What are the formulas for finding the estimate of the proportion, standard variation, and control limits?</h3>

1) The estimate of the proportion of success is

p = (number of success)/(total number of samples)

I.e., p = x/N

2) The standard deviation of the proportion of success is

$\sigma_p = \sqrt{\frac{p(1-p)}{n} }$

3) The upper and lower control limits for a control chart are:

L.C.L = p - 3 $\sigma_p$

and U.C.L = p + 3 $\sigma_p$

<h3>Calculation:</h3>

It is given that, there are 25 samples of 100 items each.

So, the total number of items i.e., the total sample size,

N = 25 × 100 = 2500

In 25 samples, a total of 135 items were found to be defective.

So, the number of defectives x = 135

a) The estimate of the proportion of defectives is p = x/N

On substituting, we get

p = 135/2500 = 0.054

b) The standard error of the proportion if the sample of size 100 is calculated by

$\sigma_p = \sqrt{\frac{p(1-p)}{n} }$

On substituting p = 0.054 and n = 100, we get

$\sigma_p = \sqrt{\frac{0.054(1-0.54)}{100} }$

= 0.0226

c) The control limits for the control chart are:

Upper control limit = p + 3 $\sigma_p$

⇒ U.C.L = 0.054 + 3(0.0226) = 0.054 + 0.0678 = 0.1218

Lower control limit = p - 3 $\sigma_p$

⇒ L.C.L = 0.054 - 3(0.0226) = 0.054 - 0.0678 = - 0.0138 ≈ 0

(Since we know that the lower control limit should not be a negative value, it is made equal to 0).

Learn more about an estimate of the proportion here:

brainly.com/question/23986522

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7 0

1 year ago