1.The measure of center that is most appropriate for this situation is the MEDIAN. This is because, one of the number given is an outlier, that is, it is much greater than the rest of the given numbers. If the mean of the number given is calculated, it will be discovered that the mean value obtained is higher than most of the scores in the data set, thus,the mean is not a suitable measure of central tendency in this case.
2. To find the median of the given numbers, arrange them in a descending order and add the two numbers in the middle then divide the value by 2.
That is, 0, 0, 1, 1, 2, 2, 2, 14.
The two numbers in the middle is 1 and 2.
Median = [1 + 2] / 2 = 3/2 = 1.5
Therefore, the median is 1.5
Answer:
k=20.
Explanation: First we find where f(x) has its local extrema: f'(x)=3x2−10x+3. The critical points are roots of the equation: 3x2−10x+3=0.
Step-by-step explanation:
The NBA fined Brooklyn Nets coach Jason Kidd $50,000 for his spilled-drink shenanigans that took place in the fourth quarter of Wednesday's 99-94 loss to the Los Angeles Lakers, the league announced Thursday
<u>Answer-</u>
2 is the upper limit for the zeros.
<u>Solution-</u>
The given function f(x) is,

For calculating the zeros,










From all the 4 roots, it can be obtained that 2 is the greatest zero.
<h2>
The value of x = - 
</h2>
Step-by-step explanation:
The given expressiona are:
and 
To find, the value of x = ?
∴ 
By crossmultiplication, we get
4(3x + 2) = 2(3x - 6)
⇒ 12x + 8 = 6x - 12
⇒ 12x - 6x = - 12 - 8
⇒ 6x = - 20
⇒ 3x = - 10
⇒ x = - 
∴ The value of x = - 
Thus, the value of x is equal to -
.