The slope of line A between (4, 8) and (0, 0) is 2. What is the slope of line A between (-2, -4) and (-4, -8)?

1 answer:

3 0

In order to find the slope of these points.. plug them in this formula y2-y1/x2-x1. so when we do we will get -8+4/-4+2. add and subtract and you will get -4/-2.. divide and you will get 2.. just so you know it had the same value because even if you choose a different number from the same line the slope will always stay the same

Hope this helps

You might be interested in

Emily spent $55 from her savings on a New Dress explain how to describe the change in Emily's savings balance in two different w

seraphim [82]

She remove (withdrew) $55 from her account. Her saving balance(d) decreased by $55

7 0

2 years ago

Read 2 more answers

What is the average amount of trail mix in each bag?

Ludmilka [50]

Answer:

4 1/4 and from all the 1/2 bags they=2 lb

8 0

3 years ago

Sin5A/SinA-cos5A/cosA=4cos2A

irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

$\frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ LHS = \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} \\ \\ = \frac{ \sin5A \:\cos A - \cos5A \: \sin A}{\sin A \:\cos A } \\ \\ = \frac{ \sin(5A -A )}{\sin A \:\cos A} \\ \\ = \frac{ \sin 4A}{\sin A \:\cos A} \\ \\ = \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ =4\cos 2A \\ \\ = RHS \\ \\ thus \\ \\ \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ hence \: proved$