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1 year ago

Exponential and log Equations 1. 2log(2x)=7

Mathematics

1 answer:

ElenaW [278]1 year ago

8 0

X = 1581.13883 is your answer

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Find the equation of the circle that satisfies the given conditions. radius 4 and center (3, -1)?

dmitriy555 [2]

the equation of this circle is (x - 3)² + (y + 1)² = 4²

5 0

3 years ago

Pleaseeee helpppp!!!!

kondor19780726 [428]

The right answer is Option A: $x=\frac{rs-t}{2}$

Step-by-step explanation:

Given expression is;

$s=\frac{2x+t}{r}$

We will solve this expression for x, therefore,

Multiplying both sides by r

$r*s=\frac{2x+t}{r}*r\\rs=2x+t$

Subtracting t from both sides

$rs-t=2x+t-t\\rs-t=2x\\2x=rs-t$

Dividing both sides by 2

$\frac{2x}{2}=\frac{rs-t}{2}\\x=\frac{rs-t}{2}$

The right answer is Option A: $x=\frac{rs-t}{2}$

Keywords: subtraction, division

Learn more about subtraction at:

#LearnwithBrainly

7 0

3 years ago

The fraction form of -1.6 is

makkiz [27]

Answer:

-1 2/3

Step-by-step explanation:

8 0

3 years ago

Ninety percent of a town’s population owns cars. If the number of cars owned is 4761, what is the population of the town?

Nuetrik [128]

We can write an equation of this, with p representing the unknown population. We know that 90% of the population owns cars:

90% * p

We also know that 4761 people own cars, which is the same as the above expression, so we write:

90% * p = 4761.

From there, you just divide both sides by 90%, or 0.9

p = 4761/0.9 = 5290

The population is 5290 people.

3 0

2 years ago

Read 2 more answers

What binomial do you have to add to the polynomial:

marshall27 [118]

Answer:

a) $-2x^2+5xy$

b) $-3y^2+5xy$

Step-by-step explanation:

Part (a)

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

$-2x^2+5xy$

$(2x^2+3y^2-5xy+1)+(-2x^2+5xy)$

$=2x^2+3y^2-5xy+1-2x^2+5xy$

$=2x^2-2x^2+3y^2-5xy+5xy+1$

$=3y^2+1$

Part (b)

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

$-3y^2+5xy$

$(2x^2+3y^2-5xy+1)+(-3y^2+5xy)$

$=2x^2+3y^2-5xy+1-3y^2+5xy$

$=2x^2+3y^2-3y^2-5xy+5xy+1$

$=2x^2+1$

7 0

2 years ago