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Cerrena [4.2K]
3 years ago
6

Alexander has nickels, dimes, and quarters in the ratio of 2:1:8, if 40 of Alexander's coins are quarters, how many nickels and

dimes does Alexander have?
Mathematics
1 answer:
ch4aika [34]3 years ago
4 0

Answer:

He has 10 nickels and 5 dimes

Step-by-step explanation:

We can take advantage of the ratio by dividing 40 by 8, giving us that every 1 in the ratio = 5. So we can multiply 2 x 5 = 10 and 1 x 5 = 5.

Hope this Helps!

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Remark

The proof is only true if m and n are equal. Make it more general.

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Answer:

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Step-by-step explanation:

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Next, multiply both sides by 3/(-2) (3 over -2)

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<em><u></u></em>

<em><u>y= -69/8</u></em>

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