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3 years ago

11

Which equation is in standard form?

2 answers:

defon3 years ago

8 0

Standard form is ax+by=c where a, b, and c are integers and a is never negative

see all of them

first one
3x+4y=10
nothing wrong

2nd one
19+3y=2x
wrong, x and y have to be on same side

3rd one
7y-7x=8
x has to be positive

4th one
8+5x=3y
x and y have to be on the same side

answer is the first one: 3x+4y=10

cricket20 [7]3 years ago

7 0

3x+4y=10 is in standard form. The standard form is Ax+By=C and this equation suits that form with A as 3, B as 4, and C as 10.

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ST,ZY,WX

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3 years ago

Read 2 more answers

How many 8ths are in a pound

Novay_Z [31]

Answer:There are 129 eighths in one pound of

Step-by-step explanation:

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2 years ago

The prices of commodities X,Y,Z are respectively x, y, z, rupees per unit. Mr. A purchases 4 units of Z and sells 3 units of X a

liubo4ka [24]

Answer:

$(x,y,z)=(1477, 1464, 1437)$

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>

Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
Mr.A earns Rs6000

So, the equation would be

$3x + 5y - 4z = 6000$

<h3>Case-2:</h3>

Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
Mr B neither lose nor gain meaning he has made 0₹

hence,

$2x - 3y + z = 0$

<h3>Case-3:</h3>

Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
Mr.C earns 13000₹

therefore,

$- x + 4y + 6z = 13000$

Thus our system of equations is

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

$\begin{cases}3x + 5y - 4z = 6000\\2x - 3y + z = 0\end{cases}\\\begin{cases}2x - 3y + z = 0\\ - x + 4y + 6z = 13000\end{cases}$

Now solve the equation accordingly:

$\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}$

Solving the equation for x and y yields:

$\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}$

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

$\implies z= \dfrac{217000}{151}$

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

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2 years ago

What is the solution to x ? <br><br> 7/3x + 1/3x = 3x + 6/3 + 5/3x

nignag [31]

7/3x+1/3x=3x+6/3+5/3x
8/3x-5/3x=3x+6/3
3/3x=3x+6/3
x=3x+6/3
x-3x=6/3
-2x=2
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x=-1

7 0

3 years ago

Need help plz help me

forsale [732]

8200? 82,000? 820,000?

4 0

3 years ago