The Expected value of a draw from the given question is; A; 0.77
We are told the face cards are K, Q, J. This means that there are 3 face cards for each of the 4 suits.
Since you earn 10 points for each face card, it means that;
total possible gain = 10 × 3 × 4 = 120
In a deck of cards, there are a total of 52 cards.
This means that;
Number of cards that are not K, Q or J = 52 - (4 × 3) = 40
Since 2 points are lost for drawing any of this 40 cards, then;
Total possible loss = 40 × 2 = 80
Expected gain = 120 - 80
Expected gain = 40
Expected value of a draw = 40/52
Expected value of a draw = 0.77
Read more about expected value at; brainly.com/question/1450915
Probability of rolling a sum of 9 or a sum that is even from two number cubes is
11/18
Explanation:
When a dice is rolled there are different ways in which
9. can be obtained, which are (3,6) or (4,5) or (5,4) or (6,3). 4 options. As in all there are
6⋅6=36 options, probability is 4/36 or 1/9.
For getting an even number as sum, we can have (1,1) or (1.3) or (1,5) or (2,2) or (2,4) or (2,6) or (3,1) or (3,3) or (3,5) or (4,2) or (4,4) or (4,6) or (5,1) or (5,3) or (5,5) or (6,2) or (6,4) or (6,6) 18 options, probability is 18/36 or 1/2.
Note that the two events (getting 9 or even sum) are mutually exclusive, the probabilities can be just added i.e. combined probability is
1/9+1/2=2+9/18i.e. 11/18
Answer:
The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)
The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)
Step-by-step explanation:
Square JKLM with vertices
We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.
In other words, the rule to rotate a point by 90° counterclockwise.
P(x, y) → P'(-y, x)
As we are given that J(1, -3), so the coordinates of J' will be:
J(1, -3) → J'(3, 1)
Therefore, the coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1).
When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.
In other words, the rule to rotate a point by 90° clockwise.
P(x, y) → P'(y, -x)
As we are given that J(1, -3), so the coordinates of J' will be:
J(1, -3) → J'(-3, -1)
Therefore, the coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)
