Answer:
Think it's 109.33
Step-by-step explanation:
look it up brodie
<span>(a.)
Let's say α is the angle that subtends from the top of the screen to horizontal eye-level.
Let β be the angle that subtends from the bottom of the screen to horizontal eye-level.
tanα = (22 + 10 - 4) / x = 28/x
α = arctan(28/x)
tanβ = (10 - 4) / x = 6/x
β = arctan(6/x)
Ɵ = α - β
Ɵ = arctan(28/x) - arctan(6/x)
(b.)
tanƟ = tan(α - β) = (tanα - tanβ) / (1 + tanα tanβ)
tanƟ = (28/x - 6/x) / [1 + (28/x)(6/x)]
tanƟ = (22/x) / [1 + (168/x²)]
tanƟ = 22x / (x² + 168)
Ɵ = arctan[22x / (x² + 168)]</span>
Answer:
The slope that is perpendicular to the line will be:
Step-by-step explanation:
Given the equation
We know that
is the slope-intercept form of a line where m is the slope and b is the y-intercept.
So, writing the equation in the slope-intercept form
here
∵
As we know that for perpendicular lines, one slope is the negative reciprocal of the other.
Therefore, the slope that is perpendicular to the line will be:
Answer:
7/10*4/10
Step-by-step explanation:
7/10 and 4/10 are both just the fraction forms of the decimal so it should work
I found h max = 64 feet
Explanation: Ok...probably you can do this differently but I would try to find the vertex of the parabola describing the trajectory: 1) derive it: h ` ( t ) = 64 − 32 t 2) set derivative equal to zero: 64 − 32 t = 0 t = 64 32 = 2 sec 3) use this value of t into your trajectory: h ( 2 ) = h max 64 ⋅ 2 − 16 ⋅ 4 = 64 feet .
