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MakcuM [25]
3 years ago
14

The attendant at a parking lot compared the number of hybrid vehicles to the total number of vehicles in the lot over a weekend.

The ratios for the three days were equivalent.
Mathematics
1 answer:
EastWind [94]3 years ago
3 0
We are given:

The ratios of the number of hybrid vehicles to the total number of vehicles in the lot over a weekend (3 days) are equivalent. 

This means that if on day 1, 100 hybrid cars parked and there are 300 cars in total, the ratio is 1 is to 3.

Therefore, on day 2 and 3, we can determine the number of hybrid cars parked given the total number of cars parked using the ratio, and vice versa. 
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Can someone please help !!!!!
Sergeu [11.5K]

Answer:

Angle A < Angle C < Angle B

CD<DE<CE

Step-by-step explanation:

Angles and the sides across from them have a specific relationship. Th smaller the angle or openness then the smaller the side. The larger the angle the larger the side. Since Angle A opposite side is 10 it is smaller than Angle B whose opposite side is 20. Since Angle C's opposite side is between the two, you can conclude that Angle A < Angle C < Angle B.

We can do the same for the other triangle knowing Angle D is 61 and Angle DCE is 60 (vertical angle theorem). Since a triangle's angles add to 180 then 180-61-60=59. Angle E is 59 degrees and since it is the smallest will have the smallest side CD. Angle DCE is the next largest and its oppposite side of DE will next followed by CE. You can conclude that CD<DE<CE

7 0
3 years ago
At a zoo, for every 6 Adult camels, there are 5 baby camels. There are a total of 44 adult and baby camels at the zoo
OleMash [197]
Whats the question asking its just a statement. there would be 4 groups of camels 6+5=11•4=44
8 0
3 years ago
Rewrite the expression by using symbols 7(x - 20)
Lelechka [254]

7 × x - 7 × 20

You could rewrite it this way, 7 x (x-20), but the answer above is better 'cause it takes away the grouping symbols

5 0
3 years ago
((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify
malfutka [58]
\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad&#10;\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}&#10;\\\\\\&#10;\left.\qquad \qquad \right.\textit{negative exponents}\\\\&#10;a^{-{ n}} \implies \cfrac{1}{a^{ n}}&#10;\qquad \qquad&#10;\cfrac{1}{a^{ n}}\implies a^{-{ n}}&#10;\qquad \qquad &#10;a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\&#10;-------------------------------\\\\

\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies&#10;\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}

\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}&#10;\\\\\\&#10;\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}
7 0
3 years ago
What is the MAD of 82, 72, 45, 91, 58, 83, 65, 87, 90, 77, 73, 89 ?<br> I'm very confused.
dsp73
MAD= mean absolute deviation. Find the mean first. So if you add all the numbers and divide by the amount of numbers. Then you do the data value subtracted by the mean. Mean= 912 divided by 12 which equals 76. 912-76= 836. Sorry if it’s wrong, I don’t remember much from learning this.
6 0
3 years ago
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