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3 years ago

6

Harold works at a men's clothing store which marks up its retail clothing by 27%

1 answer:

coldgirl [10]3 years ago

8 0

Wheres the question?

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F(x) = 4x + 7, g(x) = 3x2<br><br> Find (fg)(x).

Brums [2.3K]

F(x) = 4x + 7
g(x) = 3x²

(f · g)(x) = 3x²(4x + 7)
(f · g)(x) = 3x²(4x) + 3x²(7)
(f · g)(x) = 12x³ + 21x²

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3 years ago

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2 years ago

during a trip to the supermarket, Jim bought the following items bread $1.45 beans $0.88 toothpaste $2.90 milk $3.55 dog food $6

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3 years ago

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How do i do x/3=3 Please help!! thanks!!

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If you're looking for "x"

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3 years ago

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Can someone please help me??

dmitriy555 [2]

Answer:

I is clear that, the linear equation $5x+12=5x-7$ has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

$\frac{2}{3}\left(9x+6\right)=6x+4$

$6x+4=6x+4$

$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$

$6x+4-4=6x+4-4$

$6x=6x$

$\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}$

$6x-6x=6x-6x$

$0=0$

$\mathrm{Both\:sides\:are\:equal}$

$\mathrm{True\:for\:all}\:x$

<u>Checking the 2nd option:</u>

$5x+12=5x-7$

$\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}$

$5x+12-5x=5x-7-5x$

$\mathrm{Simplify}$

$12=-7$

$\mathrm{The\:sides\:are\:not\:equal}$

$\mathrm{No\:Solution}$

<u>Checking the 3rd option:</u>

$4x+7=3x+7$

$\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}$

$4x+7-7=3x+7-7$

$\mathrm{Simplify}$

$4x=3x$

$\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}$

$4x-3x=3x-3x$

$\mathrm{Simplify}$

$x=0$

<u>Checking the 4th option:</u>

$-3\left(2x-5\right)=15-6x$

$\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}$

$-6x+15-15=15-6x-15$

$\mathrm{Simplify}\$

$-6x=-6x$

$\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}$

$-6x+6x=-6x+6x$

$\mathrm{Simplify}$

$\mathrm{Both\:sides\:are\:equal}$

$\mathrm{True\:for\:all}\:x$

Result:

Therefore, from the above calculations it is clear that, the linear equation

$5x+12=5x-7$ has no solution.

4 0

2 years ago