Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
I do believe it is 0.46852
the answer is:
78.7 (i rounded it to the nearest tenth)
<u><em>Answer</em></u>
<em>1.) 50 mistakes per test</em>
<em>2.) 8 girls per group</em>
<em>3.) 27 pages per hour</em>
<em>4.) $1.30 per banana</em>
<em>5.) $0.50 per pencils</em>
<em>6.) 13 points per game</em>
<em>7.) $1.25 per cup of tea</em>
<em>8.) 65 liters per hour</em>
<em>9.) 25 calls per hour</em>
<em>10.) 35 words per minute</em>
<em>11.) 8 miles per liter of gas</em>
<em>12.) 0.4 eggs per day</em>
<em>13.) $28 per hour</em>
<em>14.) 3.5 miles per hour</em>
<u><em>Step-by-step explanation:</em></u>
<em>*Hope this helped*</em>
<em />
2.5 years
~You need to set this problem up in the I=PRT form. This should be your formula then, 450=2400(.075)(t). Then do 2400 times .075 and then times that by t which equals 180t. To get rid of that t then take 450 divided by 180 and you get 2.5. Remember when working with rates put them in decimal form also but your time in years.
I hope this helps you:)