12a³ + 12a² = -3a | + 3a
12a³ + 12a² + 3a = 0
3a(4a² + 4a + 1) = 0
3a(2a + 1)² = 0
3a = 0 or (2a + 1)² = 0
1) 3a = 0 | : 3
a = 0
2) (2a + 1)² = 0
2a + 1 = 0 | - 1
2a = -1 | : 2
a = -1/2
a ∈ {-1/2, 0}
Used formula:
(a + b)² = a² + 2ab + b²
Answer:
d=90
f=134
e=46
Step-by-step explanation:
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