Answer:
Step-by-step explanation:
The mean SAT score is 
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it 
) is
Next they draw a random sample of n=70 students, and they got a mean score (denoted by 
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form
and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.
<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
Hello from MrBillDoesMath!
Answer:
One solution (z = -1)
Discussion:
-2(z+3)-z=-z-4(z+2) =>
-2z -6 -z = -z -4z - 8 =>
-3z -6 = -5z -8 => add 6 to both sides
-2z = -5z -2 => add 5z to both sides
3z = -5z +5z -3 =>
3z = -3 =>
z = -1
Thank you,
MrB
The equation given in the question is
3(3x - 1) + 2(3 - x) = 0
9x - 3 + 6 - 3x = 0
6x + 3 = 0
6x = - 3
x = - (3/6)
= - (1/2)
So the value of x as has been determined above is -1/2. I hope the procedure is clear enough for you to understand.<span>You can
always use this method for solving problems that are similar in type without
requiring any help from outside. </span>
Answer:
x>2
Step-by-step explanation:
Answer:
Step-by-step explanation:
-3*j = -3j
(-3)(-1) = 3
Answer
-3j + 3 Notice the sign change. Be careful about that when signs are used with the distributive property.
