If a container is being filled at 5 pints per minute, how many gallons per second is this?

sergij07 [2.7K]

10% of what number is 300?

This means that the number is greater than 300 and in fact 10 times greater. You can create and equation. Let x be the number.

0.1x=300

x=3000

answer:3000

8 0

3 years ago

What is the exact value of tan(−π4)?<br><br> Enter your answer in the box.

kondor19780726 [428]

Answer:

What is the exact value of tan(−π4)? is 20

4 0

2 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago

A bond quoted at 93 (1/8) is equal to ___ per 1,000.00 of the face amount.

Ksju [112]

The number a bond is the percentage of the value of the bond that the bond is worth. Because the bond is quoted at 93, the bond is worth $930 per $1,000.

5 0

3 years ago

Read 2 more answers

Find the equation of the parabola that has zeros of x = –1 and x = 3 and a y-intercept of (0,–9). Question 1 options: A) y = 3x2

andrey2020 [161]

Answer:

A

Step-by-step explanation:

Given the zeros are x = - 1 and x = 3 then the factors are

(x + 1) and (x - 3) and the parabola is the product of the factors, that is

y = a(x + 1)(x - 3) ← where a is a multiplier

To find a substitute (0, - 9) into the equation

- 9 = a(0 + 1)(0 - 3) = a(1)(- 3) = - 3a ( divide both sides by - 3 )

3 = a, thus

y = 3(x + 1)(x - 3) ← expand the factors using FOIL

= 3(x² - 2x - 3) ← distribute by 3

= 3x² - 6x - 9 → A

7 0

3 years ago