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hoa [83]
3 years ago
6

Suppose a model airplane club publishes a newsletter. Expenses are $0.90 for printing and mailing each copy, plus $600 total for

research and writing. The price of the news letter is $1.50 per copy. How many copies of the newsletter must the club sell to break even? In business, the point at which income equals expenses is called the break-even point.
Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0
They would have to sell around a 1000 newspapers

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Factor 403 – 102O 2x (2x - 5)O 2. (x - 5)O 23 (223 – 10)O x (x2 – 10x)
suter [353]

We are asked to factor out the expression:

4 x^3 - 10 x

So we extract a factor of "2" from the numerical factors "4" and "10", and also a factor of "x" from each term,leading to:

2 x ( 2 x^2 - 5)

Therefore, please select the first answer option they give you in the list.

3 0
1 year ago
Jace is a songwriter who collects royalties in his songs whenever they are played in a commercial or a movie. Jace will earn $50
VashaNatasha [74]

Jace's song were played on 8 commercials and 2 movies

<h3>Further explanation</h3>

Simultaneous Linear Equations could be solved by using several methods such as :

  • <em>Elimination Method</em>
  • <em>Substitution Method</em>
  • <em>Graph Method</em>

If we have two linear equations with 2 variables x and y , then we need to find the value of x and y that satisfying the two equations simultaneously.

Let us tackle the problem!

<em>Let:</em>

<em>Number of Commercials = C</em>

<em>Number of Movies = M</em>

\texttt{ }

<em>Jaces songs were played on 6 more commercials than movies.</em>

\boxed{C = 6 + M} → <em>Equation 1</em>

\texttt{ }

<em>Jace will earn $50 every time one of his songs is played in a commercial and he will earn $140 every time one of his songs is played in a movie.</em>

<em>His total earnings in the royalties from all commercials and movies was $680.</em>

\boxed{50C + 140M = 680} → <em>Equation 2</em>

\texttt{ }

<em>Equation 1  ↔ Equation 2 :</em>

50C + 140M = 680

50 ( 6 + M ) + 140M = 680

300 + 50M + 140M = 680

190M = 680 - 300

190M = 380

M = 380 \div 190

M = 2

\texttt{ }

C = 6 + M

C = 6 + 2

C = 8

\texttt{ }

<h2>Conclusion:</h2>

The number of commercials and the number of movies in which Jaces songs where played is respectively 8 and 2

\texttt{ }

<h3>Learn more</h3>
  • Perimeter of Rectangle : brainly.com/question/12826246
  • Elimination Method : brainly.com/question/11233927
  • Sum of The Ages : brainly.com/question/11240586

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Simultaneous Linear Equations

Keywords: Simultaneous , Elimination , Substitution , Method , Linear , Equations

5 0
3 years ago
I need help please bsbshshhdbdbdbdbbdbdbfbdbdndn
Elden [556K]

Answer:

x is 3.4 i think

Step-by-step explanation:

8 0
2 years ago
The recommended single dose for a particular drug is 100 mg. How many doses can be obtained from 20 grams of the drug?
Lisa [10]

Answer:

B. 200 doses

Step-by-step explanation:

Given,

1 dose is required for 100 mg,

Since, 1 mg = 0.001 g,

⇒ 100 mg = 0.1 g

⇒ 1 dost is required for 0.1 g,

Thus, the ratio of doses and quantity ( in gram ) is \frac{1}{0.1}=10

Let x be the doses required for 20 grams,

So, the ratio of doses and quantity is \frac{x}{20}

\implies \frac{x}{20}=10

\implies x=200

Hence, 200 doses can be obtained from 20 grams of the drug.

Option 'B' is correct.

8 0
2 years ago
Please help ASAP please
lesantik [10]

The answer is 1 19/80 or 1.2375.

Hope this helps!

3 0
3 years ago
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