2 years ago

PLEASE HELP WITH THIS ONE QUESTION

Mathematics

1 answer:

Furkat [3]2 years ago

6 0

Answer:

(x-1) (x-4) is the answer

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The output is eight less than the input

horsena [70]

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——-
-10|-18
-9 |-17
-8 |-16
-7 |-15
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-5 |-13
-4 |-12
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-2|-10
-1 | -9
0 | -8
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2 |-6
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What percent of 390 is 39?

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From 1960 to 1970, the consumer price index (CPI) increased from 29.6 to 38.8. If a macaroni and cheese dinner cost $0.37 in 196

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3 years ago

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A boat is pulled toward a dock by means of a rope wound on a drum that is located 6 ft above the bow of the boat. If the rope is

Monica [59]

Answer:

Step-by-step explanation:

Given that:

The height of the dock (h) = 6

Let represent d to be the distance between the boat and the dock

Let the length of the rope between the boat and the drum be denoted by (l)

Then, the rate of change for the length of the rope be:

dl/dt = -5 ft/s

Using Pythagoras rule to determine the relationship between these values, we have:

$l^2 = h^2 +d^2$

$l^2 = 6^2 + d^2$

$l^2 = 36 + d^2$

We relate to: $2l * \dfrac{dl}{dt} = 2d* \dfrac{dd}{dt}$

From the question;

l = 34,

So to find $\dfrac{dd}{dt}$ , we get;

$d = \sqrt{l^2 - 36}$

$d = \sqrt{34^2 - 36}$

$d = \sqrt{1156- 36}$

$d = \sqrt{1120}$

d = 33.46

So, we have:

$\dfrac{dd}{dt}= \dfrac{l}{d} \times \dfrac{dl}{dt}$

$\dfrac{dd}{dt}= \dfrac{34}{33.46} \times - 5$

$\dfrac{dd}{dt}= 1.016 \times - 5$

$\dfrac{dd}{dt}=-5.08 \ ft/sec$

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2 years ago