Answer:
193
Step-by-step explanation:
9, the tens digit, is six more than 3, the ones digit. 1, the hundreds digit, is 8 less than the tens digit, 9. It can't be any other number combination than this.
Hope this helps! :)
Answer:
The six trig ratios at 3pi/2 are:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2) (undefined)
csc(3pi/2)=-1
sec(3pi/2) (undefined)
cot(3pi/2)=0
Step-by-step explanation:
If tangent is undefined then cosine would have to be 0 given that tangent is the ratio of sine to cosine.
cosine is 0 at pi/2 and 3pi/2 in the first rotation of the unit circle.
3pi/2 satisfies the given constraint.
The six trig ratios are therefore:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2)=-1/0 (undefined)
Reciprocal values:
csc(3pi/2)=-1
sec(3pi/2) undefined since cos(3pi/2)=0
cot(3pi/2)=0/-1=0
Step-by-step explanation:
Solve for xsin3⁡x+cos3⁡x=1" role="presentation" style="margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; box-sizing: inherit; display: inline; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">xsin3x+cos3x=1xsin3x+cos3x=1
sin3⁡x+cos3⁡x=1(sin⁡x+cos⁡x)(sin2⁡x−sin⁡x⋅cos⁡x+cos2⁡x)=1(sin⁡x+cos⁡x)(1−sin⁡x⋅cos⁡x)=1" role="presentation" style="margin: 0px; padding: 0px; border: 0px; font-style: normal; font-variant: inherit; font-weight: normal; font-stretch: inherit; line-height: normal; font-family: inherit; font-size: 15px; vertical-align: baseline; box-sizing: inherit; display: inline; text-indent: 0px; text-align: left; text-transform: none; letter-spacing: normal; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; position: relative;">sin3x+cos3x=1(sinx+cosx)(sin2x−sinx⋅cosx+cos2x)=1(sinx+cosx)(1−sinx⋅cosx)=1
Answer:
r = (5/8)q
Step-by-step explanation:
This means you want to express r in terms of q. Another way to say it is "solve for r."
Separate the variables by adding 4r+7q
16r = 10q
Divide by the coefficient of r
r = 10/16q
r = (5/8)q . . . . simplify
Answer:
2(x + y)
Step-by-step explanation:
You can pull out a 2 from the expression.
So divide 2x by 2 and 2y by 2.
2x/2 = x
2y/2 = y
2(x + y)
