Answer:
The question is incorrect as it lacks the "x" component. Function f(x) cannot be stated without the x, elseways it couldn't be called "f(x)"
Answer:
c=0.02(m)+30(5)
or
c= 150+0.02(m)
or
c=0.02(m)+150
or
c=30(5)+0.02(m)
Step-by-step explanation:
This is because c, or cost is equal to 30 dollars a day as a base fee or 150 total for five days plus 0.02 per mile. So, if you multiple the mileage driven by 0.02 and add 150 for the 30$ per day at 5 days. This is your equation
These are just different ways you could write that since it is clear you have a multiple choice question
Given that <span>Line WX is congruent to Line XY and Line XZ bisects Angle WXY.
We prove that triangle WXZ is congruent to triangle YXZ as follows:
![\begin{tabular} {|c|c|} Statement&Reason\\[1ex] \overline{WX}\cong\overline{XY},\ \overline{XZ}\ bisects\ \angle WXY&Given\\ \angle WXY\cong\angle YXZ & Deifinition of an angle bisector\\ \overline{XZ}\cong\overline{ZX}&Refrexive Property of \cong\\ \triangle WXZ\cong\triangle YXZ&SAS \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0AStatement%26Reason%5C%5C%5B1ex%5D%0A%5Coverline%7BWX%7D%5Ccong%5Coverline%7BXY%7D%2C%5C%20%5Coverline%7BXZ%7D%5C%20bisects%5C%20%5Cangle%20WXY%26Given%5C%5C%0A%5Cangle%20WXY%5Ccong%5Cangle%20YXZ%20%26%20Deifinition%20of%20an%20angle%20bisector%5C%5C%0A%5Coverline%7BXZ%7D%5Ccong%5Coverline%7BZX%7D%26Refrexive%20Property%20of%20%5Ccong%5C%5C%0A%5Ctriangle%20WXZ%5Ccong%5Ctriangle%20YXZ%26SAS%0A%5Cend%7Btabular%7D)
</span>
Answer:
![x = \sqrt{2} - 8\\x = -\sqrt{2} - 8](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%7B2%7D%20-%208%5C%5Cx%20%3D%20%20-%5Csqrt%7B2%7D%20-%208)
Step-by-step explanation:
To complete the square, we first have to get our equation into
form.
First we add 16x to both sides:
![x^2 + 16x + 62 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%2016x%20%2B%2062%20%3D%200)
And now we subtract 62 from both sides.
![x^2 + 16x = -62](https://tex.z-dn.net/?f=x%5E2%20%2B%2016x%20%3D%20-62)
We now have to add
to both sides of the equation. b is 16, so this value becomes
.
![x^2 + 16x + 64 = -62+64](https://tex.z-dn.net/?f=x%5E2%20%2B%2016x%20%2B%2064%20%3D%20-62%2B64)
We can now write the left side of the equation as a perfect square. We know that x+8 will be the solution because
and
.
![(x+8)^2 = -62 + 64](https://tex.z-dn.net/?f=%28x%2B8%29%5E2%20%3D%20-62%20%2B%2064)
We can now take the square root of both sides.
![x+8 = \sqrt{-62+64}\\\\ x+8 = \pm \sqrt{2}](https://tex.z-dn.net/?f=x%2B8%20%3D%20%5Csqrt%7B-62%2B64%7D%5C%5C%5C%5C%20x%2B8%20%3D%20%5Cpm%20%5Csqrt%7B2%7D)
We can now isolate x on one side by subtracting 8 from both sides.
![x = \pm\sqrt{2} - 8](https://tex.z-dn.net/?f=x%20%3D%20%5Cpm%5Csqrt%7B2%7D%20-%208)
So our solutions are
Hope this helped!