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Delvig [45]
3 years ago
5

100 POINTS AND BRAINLIEST ANSWER

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0

Answer:

Instantaneous rate of change = -13

Equation of tangent line : y= -2x +6

Step-by-step explanation:

the instantaneous rate of change of the function f(x) = 6x^2 - x at the point (-1,7)

To find instantaneous rate of change we take derivative

f(x) = 6x^2 - x

f'(x) = 12x-1

Now we plug in  -1 for x

f'(-1) = 12(-1)-1=-13

Instantaneous rate of change = -13

the equation of the line tangent to the function f(x) at the point (1,4)

f(x) = -x^2 + 5

To find slope of tangent line take derivative

f'(x) = -2x

Plug in 1 for x . given point is (1,4)

f'(1) = -2(1)=-2

so  slope = -2

use equation y-y1=m(x-x1)

y-4=-2(x-1)

y-4=-2x+2

Add 4 on both sides

y= -2x +6

polet [3.4K]3 years ago
5 0

Answer:

Just took the test,  

1)d, 3

2)a, -13

3) c, y=-2x+6

4) c, f'(a)=8a+2

Step-by-step explanation:

For #3, graph f(x)=-x^2+5. Next graph y=-2x+6. You will see that the added equation touches at exactly the point (1,4). this make it the tangent line equation

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b) If σ = 0,1612

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