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3 years ago

9

Recall that a right triangle is a triangle with one right angle.one angle of the triangle measures 89.99 degrees.can the triangl

e be a right triangle?

1 answer:

Shtirlitz [24]3 years ago

4 0

Yes because you only need a 90 degree to become a right

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Some questions have the form y = kx, where k is a number. Drag each question to the correct category below. ( X = y/2 ),( y = .1

fomenos

Answer:

<u>Has the form y = kx</u>

( y = 0.11x)

(y = 0.04x)

<u>Can be put into form y = kx</u>

(z/x = 9)

<u>Other</u>

(5 = xy)

( x = y/2)

Step-by-step explanation:

<u>y = kx</u>

( y = 0.11x)

(y = 0.04x)

<u>kx = y</u>

(z/x = 9)

-----------

( x = y/2 )

( x - 5 = y)

(5 = xy)

8 0

3 years ago

Suppose that the relation S is defined as follows.S = ( -6,0), (5,-3), (-6,-1), (-8,5)Give the domain and range of S. Write your

Angelina_Jolie [31]

The domain of a relation is all the x - values the relation can take, so:

domain = {-8, -6, 5}

The range, in addition, is all the y - values the relation can take, so:

range = {-3, -1, 0, 5}

3 0

1 year ago

What is the zeros for the equation f(x) =

sergij07 [2.7K]

Answer:

B. and E.

Step-by-step explanation:

6 0

2 years ago

Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u

cestrela7 [59]

Answer:

The amount of nuclear fuel required is 1.24 kg.

Step-by-step explanation:

From the principle of mass energy equivalence we know that energy generated by mass 'm' in an nuclear plant is

$E=m\cdot c^2$

where

'c' is the speed of light in free space

Since the power plant operates at 1200 MW thus the total energy produced in 1 year equals

$E=1200\times 10^6\times 3600\times 24\times 365=3.8\times 10^{16}Joules$

Thus using the energy produced in the energy equivalence we get

$3.8\times 10^{16}=mass\times (3\times 10^{8})^2\\\\\therefore mass=\frac{3.8\times 10^{16}}{9\times 10^{16}}=0.422kg$

Now since the efficiency of conversion is 34% thus the fuel required equals

$mass_{required}=\frac{0.422}{0.34}=1.24kg$

8 0

3 years ago

Which graph represents the funtion f(x)=3x-2/x-2

ladessa [460]

Answer:

Step-by-step explanation:

Given function is,

f(x) = $\frac{3x-2}{x-2}$

Vertical asymptote of the function,

x = 2

Horizontal asymptote of the function,

y = 3

No oblique asymptotes.

Therefore, graph having vertical and horizontal asymptotes as x = 2 and y = 3 will be the correct graph as attached.

7 0

3 years ago