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Olegator [25]
3 years ago
12

What's the mixed number for the square root 39?

Mathematics
1 answer:
avanturin [10]3 years ago
8 0
Sqrt39 = sqrt(3*13) = sqrt3 *sqrt13

hope helped 
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David has been tasked with tracking the number of bagels sold (y) at freddy's 24-hour bagel shop from 12: 00 am (x= 0) to 12: 00
ICE Princess25 [194]

Step-by-step explanation:

let say he sold 5 bagels then he would sell 5 bagels

12-5=7 , b=7

replace in 12-5=7

b=12-s

8 0
3 years ago
Question 12 Multiple Choice Worth 1 points)(07.05 MC)1086Which of the following functions best represents the graph?fix)=(x-2)(x
vlada-n [284]

The graph of a function is given. It is required to find the function that represents the graph.

Notice from the graph that the function has roots or zeros at -3,-2, and 2.

Hence, the function takes the form:

\begin{gathered} f(x)=a(x-(-3))(x-(-2))(x-2) \\ \Rightarrow f(x)=a(x+3)(x+2)(x-2) \end{gathered}

Where a is a constant to be determined.

Notice that the given graph passes through the point (0,-12).

Substitute x=0 and f(x)=-12 into the equation of the function to find a:

\begin{gathered} -12=a(0+3)(0+2)(0-2) \\ \Rightarrow-12=a(3)(2)(-2) \\ \Rightarrow-12=-12a \\ \text{ Swap the sides of the equation:} \\ \Rightarrow-12a=-12 \\ \text{ Divide both sides by }-12: \\ \Rightarrow\frac{-12a}{-12}=\frac{-12}{-12} \\ \Rightarrow a=1 \end{gathered}

Hence, the function is:

\begin{gathered} f(x)=1(x+3)(x+2)(x-2) \\ \Rightarrow f(x)=(x+2)(x+3)(x-2) \end{gathered}<h2>The third option is the answer: f(x)=(x+2)(x+3)(x-2).</h2>
5 0
1 year ago
35 Points!!
nexus9112 [7]

Answer:

- Equal midpoints of AC and BC.

- The product of the slopes of the diagonals AC and DB is -1.

Step-by-step explanation:

1. Plot the given points, as you can see in the graph attached.

2. Calculate the midpoint of AC and DB:

M_{AC}=(\frac{-5+(-1)}{2},\frac{-1+5}{2})=(-3,2)\\M_{DB}=(\frac{-9+3}{2},\frac{6+(-2)}{2})=(-3,2)

Therefore, the midpoint of AC and DB are equal.

3. Calculte the slope of the diagonals AC and DB:

m_{AC}=\frac{5-(-1)}{-1-(-5)}=\frac{3}{2}\\m_{DB}=\frac{-2-6)}{3-(-9)}=-\frac{2}{3}

4. Multiply the slopes of the diagonals:

(\frac{3}{2})(-\frac{2}{3})=-1 (AC and DB are perpendicular)

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3 years ago
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